type 8 alligation & mixtures based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 11 [SSC CGL Prelim 2008]
In a mixture of 75 litres, the ratio of milk to water is 2 : 1. The amount of water to be further added to the mixture so as to make the ratio of the milk to water 1 : 2 will be
a) 75 litres
b) 80 litres
c) 60 litres
d) 45 litres
Answer »Answer: (a)
In 75 litres of the mixture,
Milk = $2/3$ × 75 = 50 litres
Water = $1/3 × 75$ = 25 litres
Let x litres of water be added.
Then, $50/{x + 25} = 1/2$
x + 25 = 100
x = 75 litres
Question : 12 [SSCCHSL 2013]
In two alloys A and B, the ratio of zinc to tin is 5 : 2 and 3 : 4 respectively. Seven kg of the alloy A and 21 kg of the alloy B are mixed together to form a new alloy. What will be the ratio of zinc and tin in the new alloy ?
a) 2 : 3
b) 1 : 1
c) 1 : 2
d) 2 : 1
Answer »Answer: (b)
In 7 kg of alloy A,
Zinc = 5 kg, Tin = 2 kg
In 21 kg of alloy B
Zinc = ${21 × 3}/7 = 9$ kg
Tin = ${21 × 4}/7 = 12$ kg
Required ratio
= (5 + 9) : (2 + 12)
= 14 : 14 or 1 : 1
Question : 13 [SSC Delhi Police S.I.2012]
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup ?
a) $1/5$
b) $1/7$
c) $1/4$
d) $1/3$
Answer »Answer: (a)
Ratio = 4 : 1
Required quantity = $1/5$
Question : 14 [SSC CHSL 2012]
Two vessels A and B contain milk and water mixed in the ratio 8 : 5 and 5 : 2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69$3/13$% milk is:
a) 5 : 7
b) 2 : 7
c) 5 : 2
d) 3 : 5
Answer »Answer: (b)
Milk in the resulting mixture = $9/13$
= ${65 - 63}/{7 × 13} = 2/{7 × 13}$
Required ratio
= $2/{7 × 13} : 1/13$ = 2 : 7
Question : 15 [SSC CGL Prelim 2004]
There are three containers of equal capacity. The ratio of Sulphuric acid to water in the first container is 3 : 2, that in the second container is 7 : 3 and in the third container it is 11 : 4. If all the liquids are mixed together, then the ratio of Sulphuric acid to water in the mixture will be :
a) 60 : 29
b) 59 : 29
c) 61 : 28
d) 61 : 29
Answer »Answer: (d)
In the new vessel, we have.
Sulphuric acid
= $3/5 + 7/10 + 11/15$
=${18 + 21 + 22}/30 = 61/30$
Water = $2/5 + 3/10 + 4/15$
= ${12 + 9 + 8}/30 = 29/30$
Sulphuric acid : Water
= $61/30 : 29/30$= 61 : 29
IMPORTANT quantitative aptitude EXERCISES
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199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
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Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
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