Advance Math Model Questions Set 1 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11

Ram and Shyam appear for an interview for two vacancies in an organisation for the same post. The probabilities of their selection are 1/6 and 2/5 respectively. What is the probability that none of them will be selected ?

a) $1/5$

b) $1/2$

c) $5/6$

d) $3/5$

Answer: (b)

Required probability = $(1 - 1/6) × (1- 2/5) = 5/6 × 3/5 = 1/2$

Question : 12

A car is parked by an owner amongst 25 cars in a row, not at either end. On his return he finds that exactly 15 places are still occupied. The probability that both the neighbouring places are empty is

a) ${15}/{184}$

b) ${15}/{92}$

c) ${91}/{276}$

d) None

Answer: (b)

Exhaustive number of cases = $^{24}C_{14}$

Favourable cases = $^{22}C_{14}$

Probability = ${^{22}C_{14}}/{^{24}C_14} = {15}/{92}$

Question : 13

To fill a number of vacancies, an employer must hire 3 programmers from among 6 applicants, and 2 managers from among 4 applicants. What is the total number of ways in which she can make her selection ?

a) 132

b) 120

c) 1,490

d) 60

Answer: (b)

Required no. of the ways = $^6C_3 × ^4C_2$ = 20 × 6 = 120

Question : 14

A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective, is:

a) $7/{19}$

b) ${12}/{19}$

c) $4/{19}$

d) ${21}/{95}$

Answer: (a)

P (None is defective) = ${^{16}C_2}/{^{20}C_2} = ({16 × 15}/{2 × 1} × {2 × 1}/{20 × 19})$

= ${12}/{19}.$

P (at least one is defective) = 1 - ${12}/{19} = 7/{19}$

Question : 15

3 digits are chosen at random from 1,2,3,4,5,6,7,8 and 9 without repeating any digit. What is the probability that their product is odd?

a) $5/108$

b) $5/42$

c) $2/3$

d) $8/42$

Answer: (b)

Let E be the event of selecting the three numbers such that their product is odd and S be the sample space. For the product to be odd, 3 numbers choosen must be odd.

∴ n(E) = $^5C_3$

= n(S) = $^9C_3$

∴ P(E) = ${n(E)}/{n(S)} = {^5C_3}/{^9C_3} = 5/{42}$

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