time and work Model Questions & Answers, Practice Test for ssc steno grade c d 2024

Answer: (a)

Let speed of the train be x km/h and that of the car be y km/h.

Now, ${160}/x + {600}/y = 8$ ...(i)

and ${240}/x + {520}/y = {41}/5$ ...(ii)

Solving (i) and (ii), we have x = 80 km/h and

y = 100 km/h.

Answer: (c)

Let x and y finish the job in A and B days

$1/A + 1/B = 1/6 and 1/A = 1/{12}$(given)

∴ $1/{12} + 1/B = 1/6⇒1/B = 1/6 - 1/{12} = {2 - 1}/2 = 1/{12}$

So, B = 12

Hence, y alone can finish the job in 12 days

Answer: (c)

(A + B)'s one days' work = $1/10+1/{15} = 1/6$

(A + B)'s two days' work = $2/6 = 1/3$

Remaining work = 1-$1/3 = 2/3$

$1/{10}$ work is done by A in 1 day .

$2/3$ work is done by A in 10 × $2/3 = 6{2/3}$ days

Answer: (a)

Suppose the cars meet at point C after 't' hrs.

∴ AC = 50 t and BC = 30 t

∴ 50 t + 30 t = 160 160

t = ${160}/{80}$ = 2 hrs.

So, the cars will meet at 10 : 10 AM

Answer: (a)

Work done by A and B in 1 day = $1/8 + 1/{12} = 5/{24}$

2 days work of A and B = ${10}/{24}$

After 2 days A left the work.

∴ Remaining work = $1 - {10}/{24} = {14}/{24}$

work of B and C together = $1/{12} + 1/{15} = 9/{60}$

the number of days required by B and C to finish work

= ${{14}/{24}}/{9/{60}} = {14}/{24} × {60}/9 = {35}/9$

∴ Total days to complete the work

= 2 + ${35}/9 = {53}/9 = 5{8/9}$ days