profit and loss Model Questions & Answers, Practice Test for ssc mts paper 1
A manufacturer makes a profit of 15% by selling a colour TV for Rs. 5750. If the cost of manufacturing increases by 30% and the price paid by the retailer is increased by 20%, find the profit percent made by the manufacturer.
Answer: (b)
Original Cost Price = Rs. 5000
New Cost Price = 1.3 × 5000 = Rs. 6500
Price paid by retailer = 1.2 × 5750 = Rs. 6900
Profit percentage = (400/6500)×100 = 6(2/13)%
Instead of a metre scale cloth merchant uses a 120 cm scale while buying but uses an 80 cm scale while selling the same cloth. If he offers a discount of 20 per cent of cash payment, what is his overall per cent profit?
Answer: (b)
Let the cost of cloth per cm be Rs. x
As he uses 120 cm scale, so, he has 120 cm cloth cost incurred = 100x.
While selling he uses 80 cm scale, so actually he charges for $100/80 × 120$ = 150 cm of cloth
Amount obtained after 20% discount
= 0.8x × 150 = 120
∴ Profit = ${20x}/{100x} × 100$ = 20%
A got 30% concession on the label price of an article sold for Rs. 8,750 with 25% profit on the price he bought. The label price was
Answer: (b)
Let the labelled price be Rs. x
Now, C.P = $100/(100 + \text"profit" %)$ × S P
C.P = $100/(100 + 25)$ × 8750 = Rs. 7000
Now, (1 – 30% concession) label price = C.P
$(1 - 30/100)x$ = 7000
$70/100 x$ = 7000
$x = {7000 × 100}/70$
x = Rs. 10, 000
A trader sells two computers at the same price, making a profit of 30% on one and a loss of 30% on the other. What is the net loss or profit percentage on the transaction ?
Answer: (c)
Let selling price of two computers is Rs.100 each. then cost price of first computer
= $100 × 100/(100 + 30)$ = 76.92
and cost price of second computer
= $100 × 100/(100 - 30)$ = 142.86
total cost price = 142.86 + 76.92 = 219.78
Loss = 219.78 – 200 = 19.78
Loss % = $19.78/219.78 × 100$ ≈ 9% Loss
A man bought a number of oranges at 3 for a rupee and an equal number at 2 for a rupee. At what price per dozen should he sell them to make a profit of 20%?
Answer: (c)
Cost of 1 orange of 1st variety = Rs. $1/3$
Cost of 1 orange of 2nd variety = Rs. $1/2$
Cost of 1 orange after mixing = $5/12$
Profit of 20% = $5/12 × 120/100 = 1/2$
Selling price of 1 orange = Rs. $1/2$
∴ Then, SP of 12 oranges = $1/2$ × 12 = Rs. 6
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