profit and loss Model Questions & Answers, Practice Test for ssc mts paper 1

ssc mts paper 1 SYLLABUS WISE SUBJECTS MCQs

Number Systems

Percentages

Averages

Profit and Loss

Question :26

A manufacturer makes a profit of 15% by selling a colour TV for Rs. 5750. If the cost of manufacturing increases by 30% and the price paid by the retailer is increased by 20%, find the profit percent made by the manufacturer.

Answer: (b)

Original Cost Price = Rs. 5000

New Cost Price = 1.3 × 5000 = Rs. 6500

Price paid by retailer = 1.2 × 5750 = Rs. 6900

Profit percentage = (400/6500)×100 = 6(2/13)%

Question :27

Instead of a metre scale cloth merchant uses a 120 cm scale while buying but uses an 80 cm scale while selling the same cloth. If he offers a discount of 20 per cent of cash payment, what is his overall per cent profit?

Answer: (b)

Let the cost of cloth per cm be Rs. x

As he uses 120 cm scale, so, he has 120 cm cloth cost incurred = 100x.

While selling he uses 80 cm scale, so actually he charges for $100/80 × 120$ = 150 cm of cloth

Amount obtained after 20% discount

= 0.8x × 150 = 120

∴ Profit = ${20x}/{100x} × 100$ = 20%

Question :28

A got 30% concession on the label price of an article sold for Rs. 8,750 with 25% profit on the price he bought. The label price was

Answer: (b)

Let the labelled price be Rs. x

Now, C.P = $100/(100 + \text"profit" %)$ × S P

C.P = $100/(100 + 25)$ × 8750 = Rs. 7000

Now, (1 – 30% concession) label price = C.P

$(1 - 30/100)x$ = 7000

$70/100 x$ = 7000

$x = {7000 × 100}/70$

x = Rs. 10, 000

Question :29

A trader sells two computers at the same price, making a profit of 30% on one and a loss of 30% on the other. What is the net loss or profit percentage on the transaction ?

Answer: (c)

Let selling price of two computers is Rs.100 each. then cost price of first computer

= $100 × 100/(100 + 30)$ = 76.92

and cost price of second computer

= $100 × 100/(100 - 30)$ = 142.86

total cost price = 142.86 + 76.92 = 219.78

Loss = 219.78 – 200 = 19.78

Loss % = $19.78/219.78 × 100$ ≈ 9% Loss

Question :30

A man bought a number of oranges at 3 for a rupee and an equal number at 2 for a rupee. At what price per dozen should he sell them to make a profit of 20%?

Answer: (c)

Cost of 1 orange of 1st variety = Rs. $1/3$

Cost of 1 orange of 2nd variety = Rs. $1/2$

Cost of 1 orange after mixing = $5/12$

Profit of 20% = $5/12 × 120/100 = 1/2$

Selling price of 1 orange = Rs. $1/2$

∴ Then, SP of 12 oranges = $1/2$ × 12 = Rs. 6

ssc mts paper 1 IMPORTANT QUESTION AND ANSWERS

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