percentages Model Questions & Answers, Practice Test for ssc mts paper 1
In an examination Krish scores a total of 654 marks out of 950. What is his approximate percentage in the examination?
Answer: (e)
Required approximate percentage
= ${654 × 100}/950$ % = 68.84% ≈ 69%
In an examination, 70% of the students passed in the Paper I, and 60% of the students passed in the Paper II. 15% of the students failed in both the papers while 270 students passed in both the papers. What is the total number of students ?
Answer: (c)
% of students failed in paper I = 100 – 70 = 30%
% of students failed in paper II = 100 – 60 = 40%
total % of students who failed = 30 + 40 – 15 = 55%
total % of students who passed in both papers 100 – 55 = 45%
Let, total number of students be x.
Now, 45% of x = 270
${45 × x}/100 = 270 ⇒ x = 600$
By reduction of 20% in the price of oranges, one can purchase 5 oranges more for Rs. 2.50. Find the reduced price of the oranges per dozen. Find also the original price.
Answer: (d)
Let original price be Rs. x per orange.
Then, Reduced rate = (1 – 0.2)x = Rs. 0.8 x
∴$2.50/{0.8x} - 2.50/x = 5$
= $25/{8x} - 2.5/x = 5$
$x = 1/8$
∴ Original price of oranges per dozen $1/8 × 12 = $Rs. 1.5
and Reduced price = Rs. (0.8)(1.5) = Rs. 1.2
In a big garden 60% of the trees are coconut trees, 25% of the number of coconut trees are mango trees and 20% of the number of mango trees are apple trees. If the number of apple trees are 1500. then the number of trees in the garden is :
Answer: (c)
If the number of trees in the garden be x, then
$x × 60/100 × 25/100 × 20/100$ = 1500
$x × 3/5 × 1/4 × 1/5$ = 1500
$x = {1500 × 5 × 4 × 5}/3$ = 50000
In an examination, 65% students passed in Civics and 60% in History, 40% passed in both of these subjects. If 90 students failed in History and Civics both, then what is the total number of students ?
Answer: (c)
Let the total number of students be x.
Number of students passed in one or both is given by :
n(A ∪ B) = n(A) + n(B) - n(A∩ B)
= 65% of x + 60% of x – 40% of x
= $(65/100 x + 60/100 x - 40/100 x) = 85/100 x = 17/20 x$
Failed in both = $(x - 17/20x) = {3x}/20.$
∴ ${3x}/20 = 90 ⇒ x = ({90 × 20}/3) = 600$.
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