profit and loss Model Questions & Answers, Practice Test for ssc mts paper 1

Answer: (c)

Let C.P. of each clock be Rs. x.

Then, C.P. of 90 clocks = Rs. 90x.

∴ [(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40

⇒ 44x + 60x – 103.5x = 40

⇒ 0.5x = 40 ⇒ x = 80

Answer: (d)

Amount received by all the officers

= 45 × 25000 = 11,25,000

Amount received by each clerk

= $3/5 × 25000$ = 15000

Amount received by all the clerks

= 80 × 15000 = 12,00,000

Total amount of profit earned

= 11,25,000 + 12,00,000 = Rs.23.25 lakh.

Answer: (b)

Profit % = ${2006 - 1700}/1700$ × 100 = 18%

Answer: (b)

Solving this type of question by short cut.

Net profit% = $x + y + {xy}/100$

17% = $- 10 + y + {(- 10) × y}/100$ [∴ '–' for discount]

27 = $y - y/10$

27 = ${10y - y}/10$

27 × 10 = 9y

y = 30%

Hence, he must mark his goods 30% higher than their cost price.

Answer: (d)

Let the CP of two articles be 3x and 5x, respectively.

∴ SP of first article = ${{3x} × 70}/100 = {21x}/100$

SP of second article = ${{5x} × 120}/100$ = 6x

∴ Total SP = $6x + {21x}/10 = {60x + 21x}/10 = {81x}/10$

∴ Total CP = 3x + 5x = 8x

∴ Profit = ${81x}/10 – 8x = {81x - 80x}/10 = x/10$

∴ Overall percentage of gain = ${x/10 × 100}/{8x}$

= ${x × 100}/{10 × 8x}$ = 1.25%