number systems Model Questions & Answers, Practice Test for ssc mts paper 1

Answer: (d)

Let the missing figure in the expression be x.

$16/7 × 16/7 - x/7 × 9/7 + 9/7 × 9/7 = 1$

⇒ 16 × 16 – 9x + 9 × 9 = 7 × 7

⇒ 9x = 16 × 16 + 9 × 9 – 7 × 7 = 256 + 81 – 49 = 288

⇒ $x = 288/9 = 32$

Answer: (b)

Given : Divisor = 2 × remainder

∴ Divisor = 2 × 75 = 150

Also, Divisor = $2/3$ × dividend

⇒ dividend = $150 × 3/2 = 225$

Answer: (b)

Assume that the software fails a, b, and c times in a single stage, in two stage, and in all stages respectively.

∴ b + 3c = 6+ 7 + 4 = 17

but c = 4, hence b = 5

Similarly, we have

a + 2b + 3c = 15 + 12 + 8 = 35

a = 35 – 12 – 10 = 35 – 22 = 13

Hence option (b)

Answer: (d)

Out of n and n + 2, one is divisible by 2 and the other by 4, hence n (n + 2) is divisible by 8.

Also n, n + 1, n + 2 are three consecutive numbers, hence one of them is divisible by 3.

Hence n (n + 1) (n + 2) must be divisible by 24.

This will be true for any even number n.

Answer: (c)

Let a number be x

multiply by 25 we get another number y.

According to question

x × 25 = y ....(i)

Again x × 52 = 324 + y ....(ii)

Now subtract equation (i) from equation (ii)

⇒ x × 52 – x × 25 = 324 + y – y

⇒ 27x = 324

$x = 324/27 = 12$