time and work Model Questions & Answers, Practice Test for ibps so prelims 2023

Answer: (d)

Pipe 1 (Hot)→3 + X, X → Pipe 2 (cold)

Together ${X(X + 3)}/{2X + 3} = 6{2/3} min.$

= ${X(X + 3)}/{2X + 3} = 6{2/3}min. = {20}/3$

40X + 60 = 3X (X + 3)

⇒40X + 60 = 3X(X + 3)

⇒ $3X^2$ - 31X - 60 = 0

⇒ X = 12 minutes

Answer: (c)

A's one day's work = $1/32$

B's one day's work = $1/20$

(B + C)'s one day's work = $1/12$

∴ C's one day's work = $1/12-1/20=1/30$

D's one day's work = $1/24$

∴ (A + B + C + D)'s one day's work

= $1/32+1/20+1/30+1/24={15+24+16+20}/{480}$

=$5/32$

∴ Out of $5/32$ of work done,

$1/30$ of the work is done by C.

⇒ Out of Rs. 25 paid for the work, C will receive

Rs.${1/30}/{5/32}×25$ i.e. $1/30×32/5×25$ i.e. Rs.$16/3$

Answer: (c)

Rest time = Number of rest × Time for each rest

= 4 × 5 = 20 minutes

Total time to cover 5 km

= $(5/{10} × 60)$ minutes + 20 minutes = 50 minutes.

Answer: (d)

Distance covered in 2 hrs 15 min,

i.e. 2$1/4 hr = (80 × 9/4)$ hrs = 180 km

Time taken to cover remaining distance

= $({350 - 180}/{60})hrs = {17}/6 hrs = 2{5/6}$ = 2 hrs 50 min.

Total time taken = (2 hrs 15 min + 2 hrs 50 min)

= 5 hrs 5 min.

So, Anna reached city A at 10.25 a.m.

Answer: (d)

Let $C_1$ takes t hrs. Then,

∵ Distance is same.

∴ 30t = 45$(t - 5/2)$

⇒ t = ${15}/2$ hrs

∴ Distance = 30 × ${15}/2$ = 225km