Number System Model Questions & Answers, Practice Test for ibps so prelims 2023

Answer: (c)

Since the given number is divisible by 5, so 0 or 5 must come in place of #.

But, a number ending with 5 is never divisible by 8.

So, 0 will replace #.

Now, the number formed by the last three digits is 4*0,

which becomes divisible by 8, if * is replaced by 4.

Hence, digits in place of * and # are 4 and 0 respectively.

Answer: (d)

Let A = x,

B = x + 2,

C = x + 4

∴ According to the question

4x = 3(x + 4)

⇒ 4x – 3x = 12 ⇒ x = 12

∴ B = x + 2 = 12 + 2 = 14

Answer: (d)

Let the numbers be x and (x + 1),

∴ x(x + 1) = 8556

or, $x^2 + x – 8556 = 0$

or, $x^2 + 93x – 92 x – 8556 = 0$

or, $(x^2 + 93) (x – 92) = 0$

∴ x = 92

Answer: (c)

117, 120, 123, 126, ........., 333

Given series is an A.P series with

first term, a = 117,

last term l =333

and common difference, d = 3

last term, l = a + (n – 1)d

where, n = number of terms.

117 + (n – 1)3 = 333

(n – 1)3 = 216 ⇒ n = 73

Answer: (a)

Number of prime numbers less than 100 are 25