model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : A fruit vendor bought bananas at the rate of 5 for a rupee and sold them 4 for a rupee. The percent gain or loss is

(a) 25% loss

(b) 25% gain

(c) 12$1/2$% gain

(d) 12$1/2$% loss

The correct answers to the above question in:

Answer: (b)

Let the vendor buy 20 (LCM of 5 and 4) bananas.

CP of 20 bananas = Rs.4

SP of 20 bananas = Rs.5

Gain% = ${5 - 4}/4 × 100 = 25%$

Using Rule 13,

Here, a = 5, x = 1, b = 4, y = 1

His gain%= $({ay - bx}/{bx})$ × 100%

= $({5 × 1 - 4 × 1}/{4 × 1}) × 100%$

= $1/4$ × 100% = 25%

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

A man sold 20 apples for Rs.100 and gained 20%. How many apples did he buy for Rs.100?

a) 22

b) 24

c) 20

d) 25

Answer: (b)

If the CP of 20 apples be Rs.x,

then ${x × 120}/100 = 100$

$x = {100 × 100}/120$ = Rs.$250/3$

Rs.$250/3$ = 20 apples

Rs.100 = ${20 × 3 × 100}/250$ = 24 apples

Using Rule 13,

Here, a = ?, x = 100, b = 20, y = 100, Gain% = 20%

Gain% = $({ay - bx}/{bx})$ × 100%

20% = $({a × 100 - 20 × 100}/{20 × 100}) × 100%$

400 = 100a - 2000

2400 = 100a ⇒ a = 24

Question : 2

A man purchased some eggs at 3 for Rs.5 and sold them at 5 for Rs.12. Thus he gained Rs.143 in all. The number of eggs he bought is

a) 200

b) 195

c) 210

d) 190

Answer: (b)

Let he buy 15 eggs. [LCM of 5 & 3]

CP of 15 eggs = Rs.25

SP of 15 eggs = Rs.36

Gain = 36 - 25 = Rs.11

Since, Rs.11 ≡ 15 eggs

Rs.143 ≡ $15/11$ × 143 = 195 eggs

Question : 3

A man bought oranges at the rate of 8 for Rs.34 and sold them at the rate of 12 for Rs.57. How many oranges should be sold to earn a net profit of Rs.45 ?

a) 100

b) 135

c) 90

d) 150

Answer: (c)

Let the man buys 24 (LCM of 8 and 12) oranges.

C.P. of 24 oranges = $34/8 × 24$ = Rs.102

S.P. of 24 oranges = $57/12 × 24$ = Rs.114

Gain = 114 - 102 = Rs.12

Since, Rs.12 ≡ 24 oranges

Rs.45 ≡ $24/12 × 45$ = 90 oranges

Question : 4

A man buys a certain number of oranges at 20 for Rs.60 and an equal number at 30 for Rs.60. He mixes them and sells them at 25 for Rs.60. What is gain or loss per cent ?

a) Loss of 4%

b) Neither gain nor loss

c) Gain of 4%

d) Loss of 5%

Answer: (a)

Let the man buy 60 oranges (LCM of 20 and 30) of each kind. CP of the 60 oranges of the first kind

= $60/20 × 60$ = Rs.180

CP of 60 oranges of second kind $60/30 × 60$ = Rs.120

Total CP of 120 oranges = (180 + 120) = Rs.300

Their SP = $60/25 × 120$ = Rs.288

Loss = Rs.(300 - 288) = Rs.12

∴ Loss Per cent = $12/300 × 100$ = 4%

Question : 5

By selling 12 oranges for Rs.60, a man loses 25%. The number of oranges he has to sell for Rs.100, so as to gain 25% is

a) 11

b) 12

c) 10

d) 15

Answer: (b)

C.P. of 12 oranges = $60 × 100/75$ = Rs.80

For a gain of 25%,

S.P. of 12 oranges = ${80 × 125}/100$ = Rs.100

Hence, 12 Orange has to sell,

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Question : 6

A shopman bought pens at the rate of 7 for Rs.10 and sold them at a profit of 40%. How many pens would a customer get for Rs.10 ?

a) 4

b) 5

c) 6

d) 3

Answer: (b)

S.P. of 7 pens = ${10 × 140}/100$ = Rs.14

S.P. of 1 pen = $14/7$ = Rs.2

Clearly, 5 pens were sold for Rs.10

Using Rule 13,

Here, a = 7, x = 10, b = ?, y = 10, Gain% = 40%

Gain% = $({ay - bx}/{bx})$ × 100%

40 = $({7 × 10 - b × 10}/{b × 10}) × 100%$

4b = 70 - 10b

14b = 70 ⇒ b = $70/14$ ⇒ b = 5

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