model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : Mohan bought 25 books for Rs.2,000 and sold them at a profit equal to the selling price of 5 books. The selling price of 1 book is

(a) Rs.120

(b) Rs.150

(c) Rs.100

(d) Rs.200

The correct answers to the above question in:

Answer: (c)

Using Rule 1,

Let the SP of 1 book = x

SP of 25 books = 25x

According to the question,

25x - 2000 = 5x

20x = 2000 ⇒ x = $2000/20$ = 100

SP of 1 book = Rs.100

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

A shopman bought pens at the rate of 7 for Rs.10 and sold them at a profit of 40%. How many pens would a customer get for Rs.10 ?

a) 4

b) 5

c) 6

d) 3

Answer: (b)

S.P. of 7 pens = ${10 × 140}/100$ = Rs.14

S.P. of 1 pen = $14/7$ = Rs.2

Clearly, 5 pens were sold for Rs.10

Using Rule 13,

Here, a = 7, x = 10, b = ?, y = 10, Gain% = 40%

Gain% = $({ay - bx}/{bx})$ × 100%

40 = $({7 × 10 - b × 10}/{b × 10}) × 100%$

4b = 70 - 10b

14b = 70 ⇒ b = $70/14$ ⇒ b = 5

Question : 2

By selling 12 oranges for Rs.60, a man loses 25%. The number of oranges he has to sell for Rs.100, so as to gain 25% is

a) 11

b) 12

c) 10

d) 15

Answer: (b)

C.P. of 12 oranges = $60 × 100/75$ = Rs.80

For a gain of 25%,

S.P. of 12 oranges = ${80 × 125}/100$ = Rs.100

Hence, 12 Orange has to sell,

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Question : 3

A man buys a certain number of oranges at 20 for Rs.60 and an equal number at 30 for Rs.60. He mixes them and sells them at 25 for Rs.60. What is gain or loss per cent ?

a) Loss of 4%

b) Neither gain nor loss

c) Gain of 4%

d) Loss of 5%

Answer: (a)

Let the man buy 60 oranges (LCM of 20 and 30) of each kind. CP of the 60 oranges of the first kind

= $60/20 × 60$ = Rs.180

CP of 60 oranges of second kind $60/30 × 60$ = Rs.120

Total CP of 120 oranges = (180 + 120) = Rs.300

Their SP = $60/25 × 120$ = Rs.288

Loss = Rs.(300 - 288) = Rs.12

∴ Loss Per cent = $12/300 × 100$ = 4%

Question : 4

A person buys 100 cups at Rs.10 each. On the way 10 cups are broken. He sells the remaining cups at Rs.11 each. His loss per cent is

a) 1%

b) 1$1/2$%

c) $1/2$%

d) 2%

Answer: (a)

Using Rule 2

If C.P > S.P., then there will be Loss

Loss = C.P. - S.P., Loss% = ${Loss × 100}/{C.P.}$

CP of Rs.100 cups = RS.100 × 10 = Rs.1000

10 cups are broken.

SP of 90 cups = Rs.(90 ×11) = Rs.990

Loss = Rs.(1000 - 990) = Rs.10

Loss per cent = $10/1000 × 100 = 1%$

Question : 5

By selling a tape-recorder Rs. for 950, I lose 5%. What per cent shall I gain by selling it for Rs.1040?

a) 4

b) 4.5

c) 5

d) 9

Answer: (a)

Using Rule 1,

If S.P > C.P. then there will be profit

Profit = S.P. - C.P.

Profit% = ${\text"Profit" × 100}/{\text"C.P."}$

C.P. of the tape recorder

= $100/95 × 950$ = Rs.1000

Gain = 1040 - 1000 = Rs.40

% Gain = $40/1000 × 100 = 4%$

Question : 6

A fruit seller buys lemons at 2 for a rupee and sells them at 5 for three rupees. His profit per cent is

a) 15%

b) 20%

c) 10%

d) 25%

Answer: (b)

Suppose, number of lemons bought

= LCM of 2, 5, 3 = 30

CP =Rs.$(1/2 × 30)$ = Rs.$15$

SP = Rs.$(3/5 × 30)$ = Rs.18

Gain = Rs.3; Gain per cent = $3/15 × 100 = 20%$

Using Rule 13,

Here, a = 2, x = 1, b = 5, y = 3

Gain% = $({ay - bx}/{bx})$ × 100%

= $({2 × 3 - 5 × 1}/{5 × 1}) × 100%$

= $1/5 × 100%$ = 20%

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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