model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : A fruit seller buys lemons at 2 for a rupee and sells them at 5 for three rupees. His profit per cent is

(a) 15%

(b) 20%

(c) 10%

(d) 25%

The correct answers to the above question in:

Answer: (b)

Suppose, number of lemons bought

= LCM of 2, 5, 3 = 30

CP =Rs.$(1/2 × 30)$ = Rs.$15$

SP = Rs.$(3/5 × 30)$ = Rs.18

Gain = Rs.3; Gain per cent = $3/15 × 100 = 20%$

Using Rule 13,

Here, a = 2, x = 1, b = 5, y = 3

Gain% = $({ay - bx}/{bx})$ × 100%

= $({2 × 3 - 5 × 1}/{5 × 1}) × 100%$

= $1/5 × 100%$ = 20%

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

By selling a tape-recorder Rs. for 950, I lose 5%. What per cent shall I gain by selling it for Rs.1040?

a) 4

b) 4.5

c) 5

d) 9

Answer: (a)

Using Rule 1,

If S.P > C.P. then there will be profit

Profit = S.P. - C.P.

Profit% = ${\text"Profit" × 100}/{\text"C.P."}$

C.P. of the tape recorder

= $100/95 × 950$ = Rs.1000

Gain = 1040 - 1000 = Rs.40

% Gain = $40/1000 × 100 = 4%$

Question : 2

A person buys 100 cups at Rs.10 each. On the way 10 cups are broken. He sells the remaining cups at Rs.11 each. His loss per cent is

a) 1%

b) 1$1/2$%

c) $1/2$%

d) 2%

Answer: (a)

Using Rule 2

If C.P > S.P., then there will be Loss

Loss = C.P. - S.P., Loss% = ${Loss × 100}/{C.P.}$

CP of Rs.100 cups = RS.100 × 10 = Rs.1000

10 cups are broken.

SP of 90 cups = Rs.(90 ×11) = Rs.990

Loss = Rs.(1000 - 990) = Rs.10

Loss per cent = $10/1000 × 100 = 1%$

Question : 3

Mohan bought 25 books for Rs.2,000 and sold them at a profit equal to the selling price of 5 books. The selling price of 1 book is

a) Rs.120

b) Rs.150

c) Rs.100

d) Rs.200

Answer: (c)

Using Rule 1,

Let the SP of 1 book = x

SP of 25 books = 25x

According to the question,

25x - 2000 = 5x

20x = 2000 ⇒ x = $2000/20$ = 100

SP of 1 book = Rs.100

Question : 4

Ravi buys some toffees at 2 for a rupee and sells them at 5 for a rupee. His loss percent is

a) 90%

b) 30%

c) 120%

d) 60%

Answer: (d)

Let Ravi buy 10 toffees.

C.P. = Rs.5; S.P. = Rs.2

Loss % = ${5 - 2}/5 × 100$ = 60%

Using Rule: 13

Here, a = 2, x = 1, b = 5, y = 1

Loss % = $({ay - bx}/{bx})$ × 100%

= $({2 × 1 - 5 × 1}/{5 × 1}) × 100%$

=${-3}/5 × 100%$

= 60% (-ve sign shows loss)

Question : 5

A man bought pencils at the rate of 6 for Rs.4 and sold them at the rate of 4 for Rs.6. His gain% in the transaction is :

a) 80%

b) 125%

c) 75%

d) 100%

Answer: (b)

Let the number of pencils bought = LCM of 4, 6 = 12

CP of 6 pencils = Rs.4

CP of 12 pencils = Rs.8

S.P. of 4 pencils = Rs.6

S.P. of 12 pencils = Rs.18

Profit = Rs. (18 - 8) = Rs.10

Profit % = $10/8 × 100 = 125%$

Using Rule: 13

Here, a = 6, x = 4, b = 4, y = 6

Gain% = $({ay - bx}/{bx})$ × 100%

= $({6 × 6 - 4 × 4}/{4 × 4}) × 100%$

= $({36 - 16}/16) × 100%$

= $20/16 × 100% = 125%$

Question : 6

A person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of Rs.3. The total number of articles bought by him was

a) 1080

b) 540

c) 1090

d) 545

Answer: (a)

Let the person buy 10 articles.

Total CP = Rs.$(1 + 5/4)$ = Rs.$9/4$

SP of 10 articles = Rs.$2/9 × 10$ = Rs.$20/9$

Loss = Rs.$(9/4 - 20/9)$ = Rs.$({81 - 80}/36)$ = Rs.$1/36$

Now, if loss is Rs.$1/36$, number of articles = 10

If loss is Rs.3, number of articles = 36 × 10 × 3 = 1080

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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