model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : The cost price of two dozen bananas is Rs.32. After selling 18 bananas at the rate of Rs.12 per dozen, the shopkeeper reduced the rate to Rs.4 per dozen. The per cent loss is

(a) 32.4%

(b) 36.5%

(c) 25.2%

(d) 37.5%

The correct answers to the above question in:

Answer: (d)

Using Rule 2

If C.P > S.P., then there will be Loss

Loss = C.P. - S.P., Loss% = ${Loss × 100}/{C.P.}$

Total C.P. = Rs.32

Total S.P. = Rs.(18+2) = Rs.20

Loss = Rs.(32-20) = Rs.12

Loss per cent = $12/32 × 100$ = 37.5%

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

Some articles were bought at 6 for Rs.5, and sold at 5 for Rs.6. Gain per cent is :

a) 6%

b) 30%

c) 5%

d) 44%

Answer: (d)

Let number of articles bought = 6 × 5 = 30

C.P. of 30 articles = Rs.$(5/6 × 30)$ = Rs.25

S.P. of 30 articles = Rs.$(6/5 × 30)$ = Rs.36

Gain % = ${36 - 25}/25 × 100$ = 44%

Using Rule 13,

Here, a = 6, x = 5, b = 5, y = 6

Gain% = $({ay - bx}/{bx})$ × 100%

= $({6 × 6 - 5 × 5}/{5 × 5})$ × 100%

= $({36 - 25}/25) × 100% = 11/25 ×100%$ = 44%

Question : 2

Ramesh bought 10 cycles for Rs.500 each. He spent Rs.2,000 on the repair of all cycles. He sold five of them for Rs.750 each and the remaining for Rs.550 each. Then the total gain or loss % is

a) Loss of 8$1/3$%

b) Gain of 7$2/3$%

c) Gain of 8$1/3$%

d) Loss of 7$1/7$%

Answer: (d)

Using Rule 2,

Total actual C.P. = Rs.(500 × 10 + 2000) = Rs.7000

And total S.P. = Rs.(5 × 750 + 5× 550)

= Rs.(3750 + 2750) = Rs.6500

Loss = 7000 - 6500 = Rs.500

Loss percent = $500/7000 × 100 = 50/7 = 7{1}7%$

Question : 3

On selling 17 balls at Rs.720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is :

a) Rs.50

b) Rs.60

c) Rs.45

d) Rs.55

Answer: (b)

Let the CP of each ball = x.

Then, clearly the cost price of (17 - 5) balls = Rs.720

i.e., 12x = 720 ⇒ x = 60 i.e. Rs.60

Question : 4

Oranges are bought at the rate of 10 for Rs.25 and sold at the rate of 9 for Rs.25. The profit percent is

a) 10%

b) 11$1/9$%

c) 9$1/11$%

d) 12$1/2$%

Answer: (b)

Suppose the number of oranges bought

= LCM of 10 and 9 = 90

C.P. of 90 oranges = $25/10 × 90$ = Rs.225

S.P. of 90 oranges = $25/9 × 90$ = Rs.250

Profit % = $25/225 × 100 = 100/9 = 11{1}/9%$

Using Rule 13,

Here, a = 10, x = 25, b = 9, y = 25

Gain% = $({ay - bx}/{bx})$ × 100%

= $({10 × 25 - 9 × 25}/{9 × 25}) × 100%$

= $({250 - 225}/{9 × 25}) × 100% = 100/9 = 11{1}/9%$

Question : 5

100 oranges are bought for Rs.350 and sold at the rate of Rs.48 per dozen. The percentage of profit or loss is :

a) 15% gain

b) 14$2/7$% loss

c) 15% loss

d) 14$2/7$% profit

Answer: (d)

C.P. of 100 oranges = Rs.350

S.P. of 12 oranges = Rs.48

S.P. of 100 oranges

= $48/12 × 100$ = Rs.400

Profit = Rs. (400 - 350) = Rs.50

Profit % = $50/350 × 100 = 100/7 = 14{2}/7%$

Using Rule 13,

Here, a = 100, x = 350, b = 100, y = $48/12$ × 100 = 400

Gain% = $({ay - bx}/{bx})$ × 100%

= ${100 × 400 - 100 × 350}/{100 × 350}$ × 100%

= ${40 - 35}/35 × 100%$

= $100/7% = 14{2}/7$%

Question : 6

A person buys some pencils at 5 for a rupee and sells them at 3 for a rupee. His gain per cent wll be :

a) 76$2/3$%

b) 56$2/3$%

c) 66$2/3$%

d) 46$2/3$%

Answer: (c)

C.P. of 5 pencils = Rs.1.

S.P. of 5 pencils = Rs.$5/3$

Gain = $5/3 - 1 = 2/3$

Gain % = ${2/3}/1 × 100 = 66{2}/3%$

Using Rule 13,

Here, a = 5, x = 1, b = 3, y = 1

Gain% = $({ay - bx}/{bx} × 100%)$

= ${5 - 3}/3 × 100% = 200/3 = 66{2}/3%$

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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