model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : Oranges are bought at the rate of 10 for Rs.25 and sold at the rate of 9 for Rs.25. The profit percent is

(a) 10%

(b) 11$1/9$%

(c) 9$1/11$%

(d) 12$1/2$%

The correct answers to the above question in:

Answer: (b)

Suppose the number of oranges bought

= LCM of 10 and 9 = 90

C.P. of 90 oranges = $25/10 × 90$ = Rs.225

S.P. of 90 oranges = $25/9 × 90$ = Rs.250

Profit % = $25/225 × 100 = 100/9 = 11{1}/9%$

Using Rule 13,

Here, a = 10, x = 25, b = 9, y = 25

Gain% = $({ay - bx}/{bx})$ × 100%

= $({10 × 25 - 9 × 25}/{9 × 25}) × 100%$

= $({250 - 225}/{9 × 25}) × 100% = 100/9 = 11{1}/9%$

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

The cost price of two dozen bananas is Rs.32. After selling 18 bananas at the rate of Rs.12 per dozen, the shopkeeper reduced the rate to Rs.4 per dozen. The per cent loss is

a) 32.4%

b) 36.5%

c) 25.2%

d) 37.5%

Answer: (d)

Using Rule 2

If C.P > S.P., then there will be Loss

Loss = C.P. - S.P., Loss% = ${Loss × 100}/{C.P.}$

Total C.P. = Rs.32

Total S.P. = Rs.(18+2) = Rs.20

Loss = Rs.(32-20) = Rs.12

Loss per cent = $12/32 × 100$ = 37.5%

Question : 2

Some articles were bought at 6 for Rs.5, and sold at 5 for Rs.6. Gain per cent is :

a) 6%

b) 30%

c) 5%

d) 44%

Answer: (d)

Let number of articles bought = 6 × 5 = 30

C.P. of 30 articles = Rs.$(5/6 × 30)$ = Rs.25

S.P. of 30 articles = Rs.$(6/5 × 30)$ = Rs.36

Gain % = ${36 - 25}/25 × 100$ = 44%

Using Rule 13,

Here, a = 6, x = 5, b = 5, y = 6

Gain% = $({ay - bx}/{bx})$ × 100%

= $({6 × 6 - 5 × 5}/{5 × 5})$ × 100%

= $({36 - 25}/25) × 100% = 11/25 ×100%$ = 44%

Question : 3

Ramesh bought 10 cycles for Rs.500 each. He spent Rs.2,000 on the repair of all cycles. He sold five of them for Rs.750 each and the remaining for Rs.550 each. Then the total gain or loss % is

a) Loss of 8$1/3$%

b) Gain of 7$2/3$%

c) Gain of 8$1/3$%

d) Loss of 7$1/7$%

Answer: (d)

Using Rule 2,

Total actual C.P. = Rs.(500 × 10 + 2000) = Rs.7000

And total S.P. = Rs.(5 × 750 + 5× 550)

= Rs.(3750 + 2750) = Rs.6500

Loss = 7000 - 6500 = Rs.500

Loss percent = $500/7000 × 100 = 50/7 = 7{1}7%$

Question : 4

100 oranges are bought for Rs.350 and sold at the rate of Rs.48 per dozen. The percentage of profit or loss is :

a) 15% gain

b) 14$2/7$% loss

c) 15% loss

d) 14$2/7$% profit

Answer: (d)

C.P. of 100 oranges = Rs.350

S.P. of 12 oranges = Rs.48

S.P. of 100 oranges

= $48/12 × 100$ = Rs.400

Profit = Rs. (400 - 350) = Rs.50

Profit % = $50/350 × 100 = 100/7 = 14{2}/7%$

Using Rule 13,

Here, a = 100, x = 350, b = 100, y = $48/12$ × 100 = 400

Gain% = $({ay - bx}/{bx})$ × 100%

= ${100 × 400 - 100 × 350}/{100 × 350}$ × 100%

= ${40 - 35}/35 × 100%$

= $100/7% = 14{2}/7$%

Question : 5

A person buys some pencils at 5 for a rupee and sells them at 3 for a rupee. His gain per cent wll be :

a) 76$2/3$%

b) 56$2/3$%

c) 66$2/3$%

d) 46$2/3$%

Answer: (c)

C.P. of 5 pencils = Rs.1.

S.P. of 5 pencils = Rs.$5/3$

Gain = $5/3 - 1 = 2/3$

Gain % = ${2/3}/1 × 100 = 66{2}/3%$

Using Rule 13,

Here, a = 5, x = 1, b = 3, y = 1

Gain% = $({ay - bx}/{bx} × 100%)$

= ${5 - 3}/3 × 100% = 200/3 = 66{2}/3%$

Question : 6

If I would have purchased 11 articles for Rs.10 and sold all the articles at the rate of 10 for Rs.11, the profit per cent would have been :

a) 11%

b) 21%

c) 10%

d) 100%

Answer: (b)

C.P. of an article = Rs.$10/11$

S.P. of an article = Rs.$11/10$

Profit = $11/10 - 10/11$

= ${121 - 100}/110 = Rs.21/110$

Profit % = ${{21/110} × 100}/{10/11}$

= $2100/110 × 11/10$ = 21%

Using Rule 13,
If the total cost of 'a' articles having equal cost is Rs.x
and the total selling price of 'b' articles is Rs.y,
then in the transaction gain or loss per cent is given by
$({ay - bx}/{bx})$ × 100%
Where positive value signifies 'profit'
and negative value signifies 'loss'

Here, a = 11, x = 10, b = 10, y = 11

Gain% = $({ay - bx}/{bx}) × 100%$

= $({11 × 11 - 10 × 10}/{10 × 10}) × 100%$

= $({121 - 100}/100) × 100%$ = 21%

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