model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : Aniruddha sold a bicycle at a gain of 8%. Had it been sold for Rs.75 more, the gain would have been 14%. The cost price of the bicycle was

(a) Rs.1200

(b) Rs.1500

(c) Rs.1250

(d) Rs.1350

The correct answers to the above question in:

Answer: (c)

Let the CP of cycle be Rs.x.

S.P. = ${108x}/100$

${108x}/100 + 75 = {114x}/100$

108x + 7500 = 114x

114x - 108x = 7500

6x = 7500 ⇒ $x = 7500/6$ = Rs.1250

Using Rule 11,

Here, x = 8%, R= Rs.75, y = 14%

C.P. = ${R × 100}/{y - x}$

= ${75 × 100}/{14 - 8}$

= $7500/6$ = Rs.1250

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Read more sold at loss Based Quantitative Aptitude Questions and Answers

Question : 1

An article is sold at a loss of 10%. Had it been sold for Rs.9 more, there would have been a gain of 12$1/2$% on it. The cost price of the article is :

a) Rs.40

b) Rs.35

c) Rs.45

d) Rs.50

Answer: (a)

Let the cost price of the article = Rs.x

S.P. at 10% loss

= $x × 90/100 = {9x}/10$

S.P. at $12{1}/2%$ gain

=$x × {100 + 12{1}/2}/100 = {225x}/200$

According to the question

${9x}/10 + 9 = {225x}/200$

180x + 1800 = 225x

225x - 180x = 1800

45x = 1800 ⇒ x = Rs.40

Using Rule 11,
A man sells his items at a profit/loss of x%.
If he had sold it for Rs. R more,
he would have gained/lost y%.
Then. C.P. of items = $R/{(y ± x)}$ × 100
'+' = When one is profit and other is loss.
'–' = When both are either profit or loss.

Here, x = 10%, R= 9, y = 12.5%

C.P. = ${R × 100}/{y + x}$

= ${9 × 100}/{12.5 + 10} = 900/{22.5}$ = Rs.40

Question : 2

A man sold an article at a loss of 20%. If he could sell it for Rs.200 more , he would make a profit of 5%. The cost price of the article is

a) Rs.700

b) Rs.900

c) Rs.800

d) Rs.850

Answer: (c)

C.P. of article = Rs.x

First S.P. = ${80x}/100$ = Rs.${4x}/5$

According to question,

${4x}/5 + 200 = {105x}/100 = {21x}/20$

${21x}/20 - {4x}/5$ = 200

${21x - 16x}/20 = 200$

${5x}/20$ = 200 ⇒ x = 4 × 200 = Rs.800

Using Rule 11,

Here, x = 20%, R = Rs.200, y=5%

C.P. = ${R × 100}/{y + x}$

= ${200 × 100}/{5 + 20}$

= $20000/25$ = Rs.800

Question : 3

5% more is gained by selling a watch for Rs. 350 than by selling it for Rs.340. The cost price of the watch is

a) Rs.110

b) Rs.250

c) Rs.140

d) Rs.200

Answer: (d)

C.P. of watch = Rs.x (let)

Difference between selling prices

= Rs.(350 - 340) = Rs.10

According to the question,

5% of x = 10

${5x}/100$ = 10

5x = 1000 ⇒ x = $1000/5$ = Rs.200

Question : 4

Mohan sold his watch at 10% loss. If he had sold it for Rs.45 more, he would have made 5% profit. The selling price (in Rs.) of the watch was

a) 300

b) 270

c) 900

d) 110

Answer: (b)

If the C.P. of watch be Rs.x, then

First S.P. = ${9x}/10$

${105x}/100 - {9x}/10 = 45$

${105x - 90x}/100 = 45$

${15x}/100 = 45$

$x = {45 × 100}/15$ = Rs.300

S. P. = ${300 × 9}/10$ = Rs.270

Using Rule 11,

Here, x = 10%, R = Rs.45, y = 5%

C.P. = ${R × 100}/{y + x}$

= $4500/{10 + 5} = 4500/15$ = 300

S.P. = 300 - 300 × $10/100$

S.P. = Rs.270

Question : 5

A shopkeeper sold an article at a loss of 20%. But if he could sell it at Rs.200 more, he could earn a profit of 5%. The cost price of the article is

a) Rs.800

b) Rs.600

c) Rs.1,000

d) Rs.1,200

Answer: (a)

Let the C.P. of article be Rs. x.

According to the question,

${x ×105}/100 - {x × 80}/100$ = 200

105x - 80x = 20000

25x = 20000

$x = 20000/25$ = Rs. 800

Using Rule 11,

Here, x = 20%, R= 200, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${200 × 100}/{20 + 5}$

= ${200 × 100}/25$ = Rs.800

Question : 6

A T.V was sold at a profit of 5%. If it had been sold at a profit of 10%, the profit would have been Rs.1000 more. What is its cost price ?

a) Rs.20000

b) Rs.15000

c) Rs.5000

d) Rs.10000

Answer: (a)

Let the C.P. of television be Rs.x.

According to the question,

(10 - 5)% of x = 1000

x × $5/100$ = 1000

$x = {1000 × 100}/5$ = Rs.20000

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