model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : A sells a cycle to B at a profit of 20% and B sells it to C at a loss of 25%. If C bought the cycle for Rs.P, then the cost price of it for A was

(a) Rs.$1/20$P

(b) Rs.$10/9$P

(c) Rs.$9/10$P

(d) Rs.$9/20$P

The correct answers to the above question in:

Answer: (b)

C.P. for A = Rs. x (let)

According to the question,

${x × 120}/100 × 75/100$ = P

$x = {P × 100 × 100}/{120 × 75}$ = Rs.$10/9$

Using Rule 15,

Here, $ r_1 = 20%, r_2$ = 25% (Loss)

C.P. for C = C.P. for A

$({1 + r_1}/100)({1 - r_2}/100)$

P = C.P. for A

$(1 + 20/100)(1 - 25/100)$

C.P. for A = ${P × 100 × 100}/{120 × 75} = {10P}/9$

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Read more sold at loss Based Quantitative Aptitude Questions and Answers

Question : 1

If an article is sold at 5% gain instead of 5% loss, the man gains Rs.5 more. Find the cost price of that article

a) Rs.100

b) Rs.110

c) Rs.105

d) Rs.50

Answer: (d)

Let the C.P. be Rs.x

x (5% + 5%) = 5 [Being 5% gain]

100% = $5/10 × 100$ = Rs.50

Using Rule 11,

Here, x = 5%, R= Rs.5, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${5 × 100}/{5 + 5}$ = Rs.50

Question : 2

By selling 4 articles for 1 rupee, a man loses 4%. Had he sold three articles per rupee, the profit would have been :

a) 30%

b) 12%

c) 28%

d) 16%

Answer: (c)

C.P. of 1 article

= $1/4 × 100/96$ = Rs.$25/96$

C.P. of 3 articles = Rs.$75/96$

Gain = 1 - $75/96$

=${96 - 75}/96 = 21/96 = 7/32$

Gain per cent = ${7/32}/{75/96}$ × 100

= $7/32 × 96/75 × 100$ = 28%

Question : 3

A man sold an article at a loss of 20%. If he had sold it for Rs.50 more, he would have gained 5%. The cost price of the article was

a) Rs.250

b) Rs.200

c) Rs.300

d) Rs.180

Answer: (b)

Let the CP of the article be Rs.x

SP of the article at 20% loss

= $x × 80/100 = {4x}/5$

In second case,

${4x}/5 + 50 = {105x}/100$

${4x}/5 + 50 = {21x}/20$

${21x}/20 - {4x}/5 = 50$

${21x - 16x}/20 = 50$

${5x}/20$ = 50 ⇒ x = Rs.200

Using Rule 11,
A man sells his items at a profit/loss of x%.
If he had sold it for Rs. R more,
he would have gained/lost y%.
Then. C.P. of items = $R/{(y ± x)}$ × 100
'+' = When one is profit and other is loss.
'–' = When both are either profit or loss.

Here, x = 20%, R= 50, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${50 × 100}/{20 + 5}$

$= {50 × 100}/25$ = Rs.200

Question : 4

By selling 12 kg of potatoes for Rs.63, a shopkeeper gains 5%. What does he gain or lose percent by selling 50 kg of the same potatoes for Rs.247.50?

a) 1% loss

b) 1% profit

c) No profit, no loss

d) 2.5% loss

Answer: (a)

C.P. of 12 kg of potatoes

= Rs.$({63 × 100}/105)$ = Rs.60

C.P. of 50 kg of potatoes

= $60/12$ × 50 = Rs.250

Loss = Rs.(250 - 247.50) = Rs.2.5

Loss percent = ${2.5}/250 × 100$ = 1%

Question : 5

A businessman bought an article and sold it at a loss of 5%. If he had bought it for 10% less and sold it for Rs.33 more, he would have had a profit of 30%. The cost price of the article is

a) Rs.330

b) Rs.300

c) Rs.155

d) Rs.150

Answer: (d)

C.P. of the article be Rs.x

First S.P. = ${19x}/20$; C.P. = ${9x}/10$

${19x}/20 + 33$

${9x × 130}/1000 = 117/100x$

${117x}/100 - {19x}/20$ = 33

${117x - 95x}/100 = 33$

22x = 33 × 100

$x = {33 × 100}/22$ = Rs.150

Question : 6

There would be a 10% loss, if rice is sold at Rs.54 per kg. To earn a profit of 20%, the price of rice per kg will be

a) Rs.65

b) Rs.72

c) Rs.70

d) Rs.63

Answer: (b)

C.P. of rice per kg

${54 × 100}/90$ = Rs. 60

For 20% profit,

S.P. per kg. = ${60 × 120}/100$ = Rs. 72

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

C.P. = S.P$[100/{100 - \text"Loss%"}]$

= $54(100/{100 - 10})$

C.P. = Rs.60

New S.P. = C.P$[{100 + \text"Profit%"}/100]$

= $60 × ({100 + 20}/100)$ = Rs.72

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