model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

C.P. of article sold at loss = Rs.x.

C.P. of article sold at profit = Rs.(520 - x)

According to the question,

x × $10/100 = (520 - x) × 16/100$

5x = 520 × 8 - 8x

13x = 520 × 8

$x = {520 × 8}/13$ = Rs. 320

∴ Its S.P. = ${320 × 90}/100$ = Rs.288

Answer: (b)

C.P. of rice per kg

${54 × 100}/90$ = Rs. 60

For 20% profit,

S.P. per kg. = ${60 × 120}/100$ = Rs. 72

C.P. = S.P$[100/{100 - \text"Loss%"}]$

= $54(100/{100 - 10})$

C.P. = Rs.60

New S.P. = C.P$[{100 + \text"Profit%"}/100]$

= $60 × ({100 + 20}/100)$ = Rs.72

Answer: (d)

C.P. of the article be Rs.x

First S.P. = ${19x}/20$; C.P. = ${9x}/10$

${19x}/20 + 33$

${9x × 130}/1000 = 117/100x$

${117x}/100 - {19x}/20$ = 33

${117x - 95x}/100 = 33$

22x = 33 × 100

$x = {33 × 100}/22$ = Rs.150

Answer: (a)

Let the C.P be Rs.x.

First selling price = 90% of x = Rs.${9x}/10$

Second selling price = $({9x}/10 + 10)$

110% of $x = ({9x}/10 + 10)$

${11x}/10 = {9x}/10 + 10 ⇒ {2x}/10 = 10$

$x = {10 × 10}/2 = 50 = Rs.50$

Using Rule 11,

Here, x = 10%, R= 10, y = 10%

C.P. = ${R × 100}/{y + x}$

= ${10 × 100}/{10 + 10}$ = Rs.50

Answer: (d)

Let C.P. of article be Rs.x.

According of the question,

625 - x = x - 545

2 x = 625 + 545 = 1170

x = $1170/2$ = Rs.585

Required S.P. = Rs.(585 + 65) = Rs.650

Answer: (a)

Let the C.P. of article be Rs.x.

S.P. = ${175x}/200$

New S.P. = Rs.$({7x}/8 + 51.80)$

${175x}/200 + 51.8 = 106/100 × x$

${106x}/100 - {175x}/200 = 51.8$

${212x - 175x}/200 = 51.8$

37 x = 51.8 × 200

$x = {51.8 × 200}/37$ = Rs.280

Using Rule 11,

Here, x = 12.5%, R = Rs.51.80, y = 6%

C.P. = ${R × 100}/{y + x}$

= ${51.80 × 100}/{12.5 + 6}$

= $5180/{18.5}$ = Rs.280