model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

The article is sold at 11% loss.

89% of CP = Rs.178

CP = Rs.${178 × 100}/89$ = Rs.200

To gain 11%,

S.P. = 111% of Rs.200

= Rs.$111/100 × 200$ = 222

Answer: (d)

Let the first CP of the commodity be Rs.100.

First SP = Rs.110; Second CP = Rs.90

Gain% = $50/3%$

Second SP = $(100 + 50/3)%$ of 90

= Rs.$(90 × 350/300)$ = Rs.105

Difference of first and second S.P.

= Rs.(110–105) = Rs.5

Since, If the difference is Rs.5, the CP = Rs.100.

Since, If the difference be Rs.2, the

CP = $100/5 × 2$ = Rs.40

Answer: (a)

Let the C.P. of article be Rs.x.

S.P. = ${175x}/200$

New S.P. = Rs.$({7x}/8 + 51.80)$

${175x}/200 + 51.8 = 106/100 × x$

${106x}/100 - {175x}/200 = 51.8$

${212x - 175x}/200 = 51.8$

37 x = 51.8 × 200

$x = {51.8 × 200}/37$ = Rs.280

Using Rule 11,

Here, x = 12.5%, R = Rs.51.80, y = 6%

C.P. = ${R × 100}/{y + x}$

= ${51.80 × 100}/{12.5 + 6}$

= $5180/{18.5}$ = Rs.280

Answer: (d)

Let the C.P. of article be Rs.x, then

${120x}/100 - {115x}/100 = 27$

${5x}/100 = 27$

$x = {27 × 100}/5$ = Rs.540

Using Rule 11,

Here, x = 15%, R= Rs.27, y = 20%

C.P. = ${R × 100}/{y - x}$

= ${27 × 100}/{20 - 15}$

= ${27 × 100}/5$ = Rs.540

Answer: (d)

C.P. of article be Rs.x

S.P. at 15% gain

= ${115x}/100 = {23x}/20$

New C.P. = Rs.${90x}/100$

New S.P. = Rs.${90x}/100 × 125/100$ = Rs.${9x}/8$

${23x}/20 - {9x}/8 = 4$

${46x - 45x}/40 = 4$

x = 40 × 4 = Rs.160

Answer: (c)

Simple Approach

80% x + 12 = 110%

Let x be the cost price

30% x = 12 = $12/30 × 100$ = Rs.40

Using Rule 11,

Here, x = 20%, R= 12, y = 10%

C.P. = ${R × 100}/{y + x}$

= ${12 × 100}/{20 + 10}$ = Rs.40