model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Let the C.P. of article be Rs.x, then

${120x}/100 - {115x}/100 = 27$

${5x}/100 = 27$

$x = {27 × 100}/5$ = Rs.540

Using Rule 11,

Here, x = 15%, R= Rs.27, y = 20%

C.P. = ${R × 100}/{y - x}$

= ${27 × 100}/{20 - 15}$

= ${27 × 100}/5$ = Rs.540

Answer: (a)

If the C.P. of article be Rs.x, then

${105x}/100 - {90x}/100$ = 90

${15x}/100 = 90$

$x = {90 × 100}/15$ ⇒ x = Rs.600

Original S.P. = ${600 × 90}/100$ = Rs.540

Answer: (d)

The article is sold at 11% loss.

89% of CP = Rs.178

CP = Rs.${178 × 100}/89$ = Rs.200

To gain 11%,

S.P. = 111% of Rs.200

= Rs.$111/100 × 200$ = 222

Answer: (c)

Simple Approach

80% x + 12 = 110%

Let x be the cost price

30% x = 12 = $12/30 × 100$ = Rs.40

Using Rule 11,

Here, x = 20%, R= 12, y = 10%

C.P. = ${R × 100}/{y + x}$

= ${12 × 100}/{20 + 10}$ = Rs.40

Answer: (b)

Let the CP of the typewriter be Rs.x.

At 5% loss, SP = ${95x}/100$

Now, ${95x}/100 + 80 = {105x}/100$

${105x}/100 - {95x}/100 = 80$

${105x - 95x}/100 = 80$

$x = 8000/10$ = Rs.800

Using Rule 11,

Here, x = 5%, R = 80, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${80 × 100}/{5 + 5}$ = Rs.800

Answer: (d)

Let the CP of the cooker be Rs.x.

Initial SP = ${116x}/100$

Again, SP = $({116x}/100 + 20)$

${116x}/100 + 20 = {120x}/100$

116x + 2000 = 120x

4x = 2000 ⇒ $x = 2000/4$ = Rs.500

Using Rule 11,

Here, x = 16%, R = 20, Y = 20%

C.P. = ${R × 100}/{y - x}$

= ${20 × 100}/{20 - 16}$ = Rs.500