model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : A cooker is sold at a gain of 16%. If it has been sold for Rs.20 more, 20% would have been gained. The cost price of the cooker is

(a) Rs.350

(b) Rs.600

(c) Rs.400

(d) Rs.500

The correct answers to the above question in:

Answer: (d)

Let the CP of the cooker be Rs.x.

Initial SP = ${116x}/100$

Again, SP = $({116x}/100 + 20)$

${116x}/100 + 20 = {120x}/100$

116x + 2000 = 120x

4x = 2000 ⇒ $x = 2000/4$ = Rs.500

Using Rule 11,

Here, x = 16%, R = 20, Y = 20%

C.P. = ${R × 100}/{y - x}$

= ${20 × 100}/{20 - 16}$ = Rs.500

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Read more sold at loss Based Quantitative Aptitude Questions and Answers

Question : 1

A man sells his typewriter at 5% loss. If he sells it for Rs.80 more, he will gain 5%. The cost price of the typewriter is

a) Rs.1,600

b) Rs.800

c) Rs.1,200

d) Rs.1,000

Answer: (b)

Let the CP of the typewriter be Rs.x.

At 5% loss, SP = ${95x}/100$

Now, ${95x}/100 + 80 = {105x}/100$

${105x}/100 - {95x}/100 = 80$

${105x - 95x}/100 = 80$

$x = 8000/10$ = Rs.800

Using Rule 11,

Here, x = 5%, R = 80, y = 5%

C.P. = ${R × 100}/{y + x}$

= ${80 × 100}/{5 + 5}$ = Rs.800

Question : 2

A man sold an article at a loss of 20%. If he has sold that article for Rs.12 more he would have gained 10%. Find the cost price of that article :

a) Rs.60

b) Rs.22

c) Rs.40

d) Rs.30

Answer: (c)

Simple Approach

80% x + 12 = 110%

Let x be the cost price

30% x = 12 = $12/30 × 100$ = Rs.40

Using Rule 11,

Here, x = 20%, R= 12, y = 10%

C.P. = ${R × 100}/{y + x}$

= ${12 × 100}/{20 + 10}$ = Rs.40

Question : 3

A man sells an article at a gain of 15%. If he had bought it at 10% less and sold it for Rs.4 less, he would have gained 25%. The cost price of the article is

a) Rs.140

b) Rs.185

c) Rs.150

d) Rs.160

Answer: (d)

C.P. of article be Rs.x

S.P. at 15% gain

= ${115x}/100 = {23x}/20$

New C.P. = Rs.${90x}/100$

New S.P. = Rs.${90x}/100 × 125/100$ = Rs.${9x}/8$

${23x}/20 - {9x}/8 = 4$

${46x - 45x}/40 = 4$

x = 40 × 4 = Rs.160

Question : 4

Yogita sold a plasma TV at 20% gain to Shyamla. Shyamla sold it to Deepa at 10% profit. If Deepa had to pay Rs.33,000 for the plasma TV, find the cost price of the plasma TV for Yogita.

a) Rs.30,000

b) Rs.40,000

c) Rs.25,000

d) Rs.35,000

Answer: (c)

C.P. of T.V. for Yogita = Rs.x (let)

According to question,

$x × 120/100 × 110/100$ = 33000

$x = {33000 × 100 × 100}/{120 × 110}$ = Rs.25000

Using Rule 15,
If A sells an article to B at a profit (loss) of $r_1$% and B sells the same article to C at a profit (loss) of $r_2$% then the cost price of article for C will be given by
C.P of article for C
= C.P. of A × $({1 ± r_1}/100)({1 ± r_2}/100)$
(Positive and negative sign conventions are used for profit and loss.)

Here, $ r_1 = 20%, r_2 = 10%$

C.P. for Deepa = C.P. for yogita

$({1 + r_1}/100)({1 + r_2}/100)$

33000 = C.P. for Yogita

$(1 + 20/100) (1 + 10/100)$

C.P. for Yogita = ${33000 × 100 × 100}/{120 × 110}$ = Rs.25,000

Question : 5

On selling an almirah for Rs.2576, a person got a profit of 12%. Had it been bought for Rs.100 less, the profit per cent would have been

a) 11$1/9%$

b) 17$9/11%$

c) 13$1/3%$

d) 17$1/11%$

Answer: (d)

CP of the article

= $(100/112 × 2576)$ = Rs.2300

New CP = Rs.2200

Gain per cent

= ${2576 - 2200}/2200 × 100 = 17{1}/11$

Question : 6

Sandeep sells an article at a loss of 10%. Had he bought it at 20% less and sold it for Rs.55 more, he could have gained 40%. What is the cost price of the article ?

a) Rs.200

b) Rs.275

c) Rs.225

d) Rs.250

Answer: (d)

C.P. of article = Rs. x

First S.P. = Rs.${9x}/10$

Case II,

C.P. = ${80x}/100$ = Rs.${4x}/5$

According to the question,

${4x}/5 × 140/100 - {9x}/10$ = 55

${56x}/50 - {9x}/10$ = 55

${56x - 45x}/50$ = 55

11x = 50 × 55

$x = {50 × 55}/11$ = Rs.250

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