model 7 sold at loss Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : When an article is sold at a gain of 20%, it yields Rs.60 more than when it is sold at a loss of 20%. The cost price of the article is

(a) Rs.200

(b) Rs.120

(c) Rs.150

(d) Rs.140

The correct answers to the above question in:

Answer: (c)

Let the CP of the article be Rs.x.

${120x}/100 - {80x}/100 = 60$

40x = 60 × 100

$x = {60 × 100}/40$ = Rs.150

Using Rule 11,

Here, x = 20%, R= Rs.60, y= 20%

C.P. = ${R × 100}/{y + x}$

= ${60 × 100}/{20 + 20}$

= $6000/40$ = Rs.150

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Read more sold at loss Based Quantitative Aptitude Questions and Answers

Question : 1

Sandeep sells an article at a loss of 10%. Had he bought it at 20% less and sold it for Rs.55 more, he could have gained 40%. What is the cost price of the article ?

a) Rs.200

b) Rs.275

c) Rs.225

d) Rs.250

Answer: (d)

C.P. of article = Rs. x

First S.P. = Rs.${9x}/10$

Case II,

C.P. = ${80x}/100$ = Rs.${4x}/5$

According to the question,

${4x}/5 × 140/100 - {9x}/10$ = 55

${56x}/50 - {9x}/10$ = 55

${56x - 45x}/50$ = 55

11x = 50 × 55

$x = {50 × 55}/11$ = Rs.250

Question : 2

On selling an almirah for Rs.2576, a person got a profit of 12%. Had it been bought for Rs.100 less, the profit per cent would have been

a) 11$1/9%$

b) 17$9/11%$

c) 13$1/3%$

d) 17$1/11%$

Answer: (d)

CP of the article

= $(100/112 × 2576)$ = Rs.2300

New CP = Rs.2200

Gain per cent

= ${2576 - 2200}/2200 × 100 = 17{1}/11$

Question : 3

Yogita sold a plasma TV at 20% gain to Shyamla. Shyamla sold it to Deepa at 10% profit. If Deepa had to pay Rs.33,000 for the plasma TV, find the cost price of the plasma TV for Yogita.

a) Rs.30,000

b) Rs.40,000

c) Rs.25,000

d) Rs.35,000

Answer: (c)

C.P. of T.V. for Yogita = Rs.x (let)

According to question,

$x × 120/100 × 110/100$ = 33000

$x = {33000 × 100 × 100}/{120 × 110}$ = Rs.25000

Using Rule 15,
If A sells an article to B at a profit (loss) of $r_1$% and B sells the same article to C at a profit (loss) of $r_2$% then the cost price of article for C will be given by
C.P of article for C
= C.P. of A × $({1 ± r_1}/100)({1 ± r_2}/100)$
(Positive and negative sign conventions are used for profit and loss.)

Here, $ r_1 = 20%, r_2 = 10%$

C.P. for Deepa = C.P. for yogita

$({1 + r_1}/100)({1 + r_2}/100)$

33000 = C.P. for Yogita

$(1 + 20/100) (1 + 10/100)$

C.P. for Yogita = ${33000 × 100 × 100}/{120 × 110}$ = Rs.25,000

Question : 4

A book seller sells a book at a profit of 10%. If he had bought it at 4% less and sold it for Rs.6 more, he would have gained 18$3/4%$. The cost price of the book is

a) Rs.130

b) Rs.160

c) Rs.140

d) Rs.150

Answer: (d)

Let the CP of the book be Rs.x.

Initial SP = $110/100 × x = 1.1 x$

New CP = 0.96 x

New SP = $(100 + 75/4)%$ of 0.96x

=$475/400 × 0.96x = 1.14 x$

Therefore, 1.14 x –1.1x = 6

0.04 x = 6

$x = 6/{0.04} = 600/4 = 150$

CP = Rs.150

Question : 5

The profit earned by a shopkeeper by selling a bucket at a gain of 8% is Rs.28 more than when he sells it at a loss of 8%. The cost price (in Rupees) of the bucket is

a) 170

b) 165

c) 190

d) 175

Answer: (d)

Let the C.P. of bucket be Rs.x.

According to the question,

${108x}/100 - {92x}/100$ = 28

${16x}/100$ = 28

$x = {28 × 100}/16$ = Rs.175

Question : 6

A book vendor sold a book at a loss of 20%. Had he sold it for Rs.108 more, he would have earned a profit of 30%. Find the cost price of the book ?

a) Rs.216

b) Rs.432

c) Rs.648

d) Rs.240

Answer: (a)

If the cost price of the book be Rs.x, then

${x × 80}/100 + 108 = {x × 130}/100$

${5x}/10 = 108 ⇒ x = Rs.216$

Using Rule 11

Here, x = 20%, R= Rs.108, y=30%

C.P. = ${R × 100}/{y + x}$

= ${108 × 100}/{30 + 20}$

= $10800/50$ = Rs.216

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