model 3 reducing & exceeding prices Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on percentage topic of quantitative aptitude

Questions : When the price of sugar decreases by 10%, a man could buy 1 kg more for Rs.270. Then the original price of sugar per kg is

(a) Rs.25

(b) Rs.27

(c) Rs.32

(d) Rs.30

The correct answers to the above question in:

Answer: (d)

Let the original price of sugar be Rs.x/kg.

New price = Rs.${9x}/10$ /kg

$270/{{9x}/10} - 270/x =1$

$300/x - 270/x = 1 ⇒ 30/x = 1$ ⇒ x = Rs.30 /kg

Using Rule 31,

New price = ${10 × 270}/{100 × 1}$ = Rs.27

Let the original price be Rs. x

$x - {10x}/100 = 27 ⇒ {90x}/100 = 27$

$x = 2700/90$ ⇒ x = 30

∴ Original price = Rs.30 per kg.

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Read more reducing exceeding prices Based Quantitative Aptitude Questions and Answers

Question : 1

The price of sugar is reduced by 20%. Now a person can buy 500g more sugar for Rs.36. The original price of the sugar per kilogram was

a) Rs.14.40

b) Rs.15.60

c) Rs.16.50

d) Rs.18

Answer: (d)

Let the original price of sugar = Rs.x /kg.

Reduced price of sugar = 80% of x

= ${x × 80}/100 = Rs.{4x}/5$kg

$36/{{4x}/5} - 36/x = 1/2$

$45/x - 36/x = 1/2$

$9/x = 1/2$ ⇒ x = 9 × 2 = Rs.18/Kg

Using Rule 31,

New price = ${20 × 36}/{100 × 500/100}$ = Rs.14.4

Let the original price be Rs x A.T.Q.

$x - {20x}/100$ = 14.4

${80x}/100$ = 14.4

$x = 144/8$ ⇒ x =18

∴ Original price = Rs.18

Question : 2

A reduction of 20% in the price of an apple enables a man to buy 10 apples more for Rs.54. The reduced price of apples per dozen is

a) Rs.4.32

b) Rs.10.80

c) Rs.14.40

d) Rs.12.96

Answer: (d)

Let the original price of apples be Rs.x/ dozen

New price = Rs.${4x}/5$ /dozen

$54/{{4x}/5} - 54/x = 10/12$

$54(5/{4x} - 1/x) = 5/6$

$54({5 - 4}/{4x}) = 5/6$

$54/{4x} =5/6 ⇒ 4x = {54 × 6}/5$

${4x}/5 = {54 × 6}/{5 × 5}$ = Rs.12.96

Using Rule 31,

Reduced price = ${20 × 54}/{100 × 10/12}$

= $1080/1000 × 12$ = Rs.12.96 per kg

Question : 3

If the price of sugar increases by 20%, one can buy 2 kg less for Rs. 50. What is the amount of sugar that could be bought before price hike?

a) 10 kg.

b) 14 kg.

c) 16 kg.

d) 12 kg.

Answer: (d)

Let original price of sugar be Rs. x per kg.

New price= Rs.$({120x}/100) =Rs.({6x}/5)$per kg.

According to the question,

$50/x - 50/{{6x}/5} = 2$

$50/x - {50 × 5}/{6x} = 2$

$50/x - 125/{3x} = 2$

${150 – 125}/{3x} = 2$

$6x = 25 ⇒ x = Rs.25/6$ kg.

Required quantity of sugar = $50/x$

= $50/{25/6} = {50 × 6}/25 = 12$kg.

Question : 4

A reduction of 10% in the price of sugar enables a housewife to buy 6.2 kg more for Rs.1116. The reduced price per kg is

a) Rs.12

b) Rs.16

c) Rs.18

d) Rs.14

Answer: (c)

Reduced price of 6.2kg of sugar

= 10% of Rs.1116 = Rs.111.6

Reduced price per kg

= Rs.$(111.6/6.2)$ = Rs.18

Using Rule 31,

New price = ${10 × 1116}/{100 × 6.2}$

= $1116/62$ = Rs.18

Question : 5

The Government reduced the price of sugar by 10 per cent. By this a consumer can buy 6.2 kg more sugar for Rs.837. The reduced price per kg of sugar is

a) Rs.12.50

b) Rs.13.50

c) Rs.14.00

d) Rs.13.00

Answer: (b)

10 percent of Rs.837

= $10/100 × 837$ = Rs.83.7

Reduced per kg price

= $83.7/6.2$ = Rs.13.50

Using Rule 31,

If the price of an article is reduced by a% and buyer gets c kg more for some Rs. b, the new price per kg of article = ${ab}/{100 × c}$

Reduced price per kg

= ${10 × 837}/{100 × 6.2}$ = Rs.13.50

Question : 6

A reduction of 25% in the price of rice enables a person to buy 10 kg more rice for Rs.600. The reduced per kg price of rice is

a) Rs.30

b) Rs.20

c) Rs.15

d) Rs.25

Answer: (c)

Let original price of rice per kg = Rs.x (let)

New price of rice per kg = Rs.${3x}/4$

$600/{{3x}/4} - 600/x = 10$

$600(4/{3x} - 1/x) = 10$

$600({4 - 3}/{3x})$ = 10

$600/{3x} = 10 ⇒ x = 600/30 = Rs.20$

New price = ${3x}/4 = {3 × 20}/4$ = Rs.15/kg

Method 2: Simple Approach,

If the price of an article is reduced by a% and buyer gets c kg more for some Rs.b, the new price per kg of article = ${ab}/{100 × c}$

= ${25 × 600}/{100 × 10}$ = Rs.15

Using Rule 31,

Reduced price per kg = ${25 × 600}/{100 × 10}$ = Rs.15

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