model 10 reduced/increased price of an article Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Selling price = 405 × 110% = Rs.445.50

Remaining apples = 10 – 1= 9 kg

Therefore, the remaining apples (per kg) cost

=$445.50/9$ = Rs.49.50

Answer: (d)

Let the original price = x per dozen

New price = (x – 4) per dozen

Original number of pins = $48/x$ dozens

New number of pins = $48/{x – 4}$ dozens

According to the question,

$48/{x -4} – 48/x = 1$

⇒ $48({x – x + 4}/{x(x - 4)})$= 1

⇒ x (x – 4) = 48 × 4

⇒ $x^2 – 4x – 192 = 0$

⇒ $x^2 – 16x + 12x – 192$ = 0

⇒ x (x – 16) + 12 (x – 16) = 0

⇒ (x – 16) (x + 12) = 0

⇒ x = 16, because the price of pins can not be negative.

x ≠–12

New price = 16 – 4 = Rs.12 per dozen

Answer: (d)

Cost of production of article = Rs.100 (let)

S.P. = Rs.133

New cost of production = Rs.112

S.P. = ${133 × 110}/100$ = Rs.146.30

Profit per cent = $({146.3 – 112}/112) × 100$

= ${34.3 × 100}/112 = 3430/112$

= $245/8 = 30{5}/8%$

Answer: (a)

Original price of rice = Rs.x per kg.

New price = ${80x}/100$ = Rs.${4x}/5$ per kg

According to the question,

$1200/{{4x}/5} – 1200/x$ = 5

${1200 × 5}/{4x} – 1200/x$ = 5

$1500/x – 1200/x$ = 5

$300/x$ = 5 ⇒ 5x = 300

$x = 300/5$ = Rs.60 per kg

New price of rice

= Rs.$({4 × 60}/5)$ per kg = Rs.48 per kg

Answer: (a)

Let the C.P. of article be x.

105% of x – 80% of x = 100

25% of x = 100

$x = {100 × 100}/25$ = Rs.400

Answer: (d)

Due to fall in price, there is a saving of 20% of Rs.100 i.e., Rs.20.

With this amount the purchaser purchases 4 kg. of salt.

Reduced price of salt per kg = $20/4$ = Rs.5