model 10 reduced/increased price of an article Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on profit & loss topic of quantitative aptitude
(a) Rs.6.25
(b) Rs.6.50
(c) Rs.4
(d) Rs.5
The correct answers to the above question in:
Answer: (d)
Due to fall in price, there is a saving of 20% of Rs.100 i.e., Rs.20.
With this amount the purchaser purchases 4 kg. of salt.
Reduced price of salt per kg = $20/4$ = Rs.5
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Read more reduce increase article price Based Quantitative Aptitude Questions and Answers
Question : 1
A tradesman sold an article at a loss of 20%. If the selling price had been increased by Rs.100, there would have been a gain of 5%. The cost price of the article was :
a) Rs.400
b) Rs.250
c) Rs.200
d) Rs.25
Answer »Answer: (a)
Let the C.P. of article be x.
105% of x – 80% of x = 100
25% of x = 100
$x = {100 × 100}/25$ = Rs.400
Question : 2
A reduction of 20% in the price of rice enables a buyer to buy 5 kg more for rupees 1200. The reduced price per kg of rice will be:
a) 48
b) 60
c) 36
d) 45
Answer »Answer: (a)
Original price of rice = Rs.x per kg.
New price = ${80x}/100$ = Rs.${4x}/5$ per kg
According to the question,
$1200/{{4x}/5} – 1200/x$ = 5
${1200 × 5}/{4x} – 1200/x$ = 5
$1500/x – 1200/x$ = 5
$300/x$ = 5 ⇒ 5x = 300
$x = 300/5$ = Rs.60 per kg
New price of rice
= Rs.$({4 × 60}/5)$ per kg = Rs.48 per kg
Question : 3
The reduction of 12 in the selling price of an article will change 5% gain into 2$1/2%$ loss. The cost price of the article is
a) Rs.80
b) Rs.100
c) Rs.140
d) Rs.160
Answer »Answer: (d)
If the C.P. of article be Rs.x, then
$x × (105 – {195}/2)$% = 12
$x × 15/200 = 12 ⇒ x = {12 × 200}/15$ = Rs.160
Question : 4
A reduction of 15% in the price of apples would enable a purchaser to get 2 kg more apples for Rs.240. The new price (per kg) of apples is
a) Rs.20
b) Rs.36
c) Rs.15
d) Rs.18
Answer »Answer: (d)
Let the original rate = x per kg.
New rate = 85% of x = ${85x}/100 = {17x}/20$
Original quantity for Rs.240 = $240/x$
New quantity = 240 × $20/{17x} = 4800/{17x}$
$4800/{17x} – 240/x$ = 2
${4800 – 4080}/{17x}$ = 2
$720/{17x} = 2 ⇒ x = 720/{2 × 17}$
Original rate per kg = Rs.$720/34$
Reduced rate = Rs.${17x}/20$
= Rs.$(17/20 × 720/34)$ = Rs.18
GET profit & loss PRACTICE TEST EXERCISES
Model 1 Basic Concepts of C.P and S.P
model 2 gain lost percentage
model 3 gain/loss % with C.P/S.P
model 4 sold & brought
model 5 marked price
model 6 sold in circular path
model 7 sold at loss
model 8 two article sold in different rates
model 9 selling an article & interchanging its values
model 10 reduced/increased price of an article
model 11 ratio & partnership
profit & loss Shortcuts and Techniques with Examples
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Model 1 Basic Concepts of C.P and S.P
Defination & Shortcuts … -
model 2 gain lost percentage
Defination & Shortcuts … -
model 3 gain/loss % with C.P/S.P
Defination & Shortcuts … -
model 4 sold & brought
Defination & Shortcuts … -
model 5 marked price
Defination & Shortcuts … -
model 6 sold in circular path
Defination & Shortcuts … -
model 7 sold at loss
Defination & Shortcuts … -
model 8 two article sold in different rates
Defination & Shortcuts … -
model 9 selling an article & interchanging its values
Defination & Shortcuts … -
model 10 reduced/increased price of an article
Defination & Shortcuts … -
model 11 ratio & partnership
Defination & Shortcuts …
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