model 11 percentage with ratios Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on percentage topic of quantitative aptitude

Questions : If 35% of A's income is equal to 25% of B's income, then the ratio of A's income to B's income is

(a) 4 : 7

(b) 4 : 3

(c) 5 : 7

(d) 7 : 5

The correct answers to the above question in:

Answer: (c)

According to the question, A × 35% = B × 25%

$A/B = 25/35 = 5/7$

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Read more ratios based Based Quantitative Aptitude Questions and Answers

Question : 1

The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 25% of the girls are scholarship holders, then the percentage of the students, who do not get the scholarship, is :

a) 60%

b) 55%

c) 75%

d) 78%

Answer: (d)

Boys = 30, Girls = 20 (let)

Boys getting no scholarship = 24

Girls getting no scholarship = 15

Sum = 24 + 15 = 39

Required percentage = $39/50 × 100$ = 78%

Question : 2

Rama's expenditures and savings are in the ratio 5 : 3. If her income increases by 12% and expenditure by 15%, then by how much per cent do her savings increase ?

a) 8%

b) 13%

c) 7%

d) 12%

Answer: (c)

Let Rama's expenditure = 5x

Savings = 3x

Rama's income = 5x + 3x = 8x

After increase,

Rama's income = $112/100 × 8x = 8.96 x$

Rama's expenditure = ${5x × 115}/100 = 5.75x$

Rama's savings = (8.96x – 5.75x) = 3.21x

Rama's saving percent = $({3.21x - 3x}/{3x})×100$

= $0.21/3 × 100 = 7$

Question : 3

In a class, the number of girls is 20% more than that of the boys. The strength of the class is 66. If 4 more girls are admitted to the class, the ratio of the number of boys to that of the girls is

a) 1 : 4

b) 3 : 5

c) 3 : 4

d) 1 : 2

Answer: (c)

Let number of boys be x.

Then, $x + 120/100x = 66 ⇒ x + {6x}/5 = 66$

${5x + 6x}/5 = 66 ⇒ x = {66 × 5}/11 = 30$

Number of girls = 66 - 30 = 36

New ratio = 30 : (36 + 4) = 30 : 40 = 3 : 4

Question : 4

If 30% of A = 0.25 of B = $1/5$ of C, then A : B : C is equal to :

a) 6 : 5 : 4

b) 10 : 12 : 15

c) 5 : 24 : 5

d) 5 : 6 : 4

Answer: (b)

30% of A = 25% of B

30 A = 25 B

A : B = 25 : 30 = 5 : 6

Again, 25% of B = 20% of C

25 B = 20C ⇒ 5B = 4C

B : C = 4 : 5

A : B : C = 5 × 4 : 4 × 6 : 6 × 5

= 20 : 24 : 30 = 10 : 12 : 15

Question : 5

Two numbers are in the ratio 2 : 3. If 20% of the smaller number added to 20 is equal to the sum of 10% of the larger number and 25, then the smaller number is

a) 180

b) 200

c) 160

d) 100

Answer: (d)

Let the numbers be 2x and 3x.

According to the question,$(20/100 × 2x) + 20$

= $(10/100 × 3x) + 25$

${2x}/5 + 20 = {3x}/10 + 25$

${2x}/5 - {3x}/10$ = 25 - 20

${4x - 3x}/10$ = 5 ⇒ x = 50

The smaller number = 2x = 100

Question : 6

The ratio of the number of boys to that of girls in a village is 3 : 2. If 30% of boys and 70% of girls appeared in an examination, the ratio of the number of villagers, appreared in the examination to that not appeared in the same examination is

a) 1 : 1

b) 27 : 23

c) 23 : 27

d) 9 : 14

Answer: (c)

Boys in the village = 3x

Girls in the village = 2x

Villagers who appeared in the examination

= ${3x × 30}/100 + {2x × 70}/100$

= ${9x}/10 + {14x}/10 = {23x}/10$

Villagers who did not appear in the examination

= ${3x × 70}/100 + {2x × 30}/100$

= ${21x}/10 + {6x}/10 = {27x}/10$

Required ratio = ${23x}/10 : {27x}/10$ = 23 : 27

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