model 11 percentage with ratios Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : In what ratio must 25% hydrochloric acid be mixed with 60% hydrochloric acid to get a mixture of 40% hydrochloric acid ?

(a) 3 : 4

(b) 12 : 5

(c) 4 : 3

(d) 5 : 12

The correct answers to the above question in:

Answer: (a)

Required ratio = 15 : 20 = 3 : 4

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Read more ratios based Based Quantitative Aptitude Questions and Answers

Question : 1

The difference of two numbers is 15% of their sum. The ratio of the larger number to the smaller number is

a) 17 : 11

b) 23 : 11

c) 11 : 9

d) 23 : 17

Answer: (d)

Let the numbers be x and y where x > y.

Then, x - y =$15/100$(x + y)

x – y = $3/20$(x + y)

20x – 20y = 3x + 3y

20x – 3x = 20y + 3y

17x = 23y ⇒ $x/y = 23/17$

Question : 2

If 30% of (B – A) = 18% of (B + A), then the ratio A : B is equal to

a) 5 : 4

b) 5 : 9

c) 1 : 4

d) 4 : 1

Answer: (c)

$(B – A) × 30/100 = (B + A) × 18/100$

${B - A}/{B + A} = 18/30 = 3/5$

By componendo and dividendo,

${2B}/{- 2A} = {3 + 5}/{3 - 5} = 8/{-2} = 4/{-1}$

$B/A = 4/1$ = A : B = 1 : 4

Question : 3

The ratio of two numbers is 4:5 when the first is increased by 20% and the second is decreased by 20%, the ratio of the resulting numbers is

a) 5 : 6

b) 6 : 5

c) 5 : 4

d) 4 : 5

Answer: (b)

Let the numbers be 4x and 5x.

After corresponding increase or decrease,

Required ratio = ${4x} × 120/100 : {5x} × 80/100$

= 12x : 10x = 6 : 5

Question : 4

If 10% of m is the same as 20% of n, then m : n is equal to :

a) 1 : 10

b) 1 : 20

c) 1 : 2

d) 2 : 1

Answer: (d)

10% of m = 20% of n

$10/100 × m = 20/100 × n$

$m/n = 10/5 = 2/1$

m : n = 2 : 1

Question : 5

The ratio of syrup and water in a mixture is 3 : 1, then the percentage of syrup in this mixture is :

a) 66$2/3$%

b) 33$1/3$%

c) 25%

d) 75%

Answer: (d)

Percentage of syrup = $3/4$ × 100 = 75%

Question : 6

The expenses on rice, fish and oil of a family are in the ratio 12 : 17 : 3. The prices of these articles are increased by 20%, 30% and 50% respectively. The total expenses of family on these articles are increased by

a) 56$1/8$%

b) 28$1/8$%

c) 7$1/8$%

d) 14$1/8$%

Answer: (b)

Let the initial expenses on rice, fish and oil be Rs.12x, Rs.17x and Rs.3x respectively.

Total expenditure = Rs.(12x + 17x + 3x) = Rs.32 x

After increase,

Expenditure on rice = $120/100 ×12x = Rs.14.4x$

Expenditure on fish = $130/100 × 17x = Rs.22.1x$

Expenditure on oil = $150/100 × 3x = Rs.4.5x$

Total expenditure =Rs.(14.4 x + 22.1x + 4.5 x) =Rs.41 x

Increase = Rs.(41x – 32x) = Rs.9x

Percentage increase =${9x}/{32x} × 100 =225/8 = 28{1}/8$%

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