model 11 percentage with ratios Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : There is a ratio of 5: 4 between two numbers. If 40 % of the first number is 12, then what would be 50 % of the second number?

(a) 18

(b) Data Inadequate

(c) 24

(d) 12

The correct answers to the above question in:

Answer: (d)

Let the numbers be 5x and 4x respectively

According to the question,

5x × $40/100$ = 12

2x = 12 ⇒ x = 6

4x of 50% = 4 × 6 × $1/2$ = 12

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Read more ratios based Based Quantitative Aptitude Questions and Answers

Question : 1

If 10% of x is 3 times 15% of y, then find x : y.

a) 8 : 3

b) 11 : 4

c) 9 : 2

d) 7 : 2

Answer: (c)

According to the question,

$x × 10/100 = 3 × y × 15/100$

10x = 45y

$x/y = 45/10 = 9/2$

Question : 2

The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 30% of the girls are scholarship holders, then the percentage of students, who do not get scholarship, is

a) 75%

b) 76%

c) 72%

d) 50%

Answer: (b)

Let the number of boys = 3x and that of girls = 2x

Number of boys who do not hold scholarship = 80% of 3x

= $3x × 80/100 = {12x}/5$

Number of girls who do not hold scholarship

= $2x × 70/100 = {14x}/10$

Number of students who do not hold scholarship

= ${12x}/5 + {14x}/10 = {24x + 14x}/10 = {38x}/10$

Required percentage = ${{38x}/10}/{5x} × 100 = 38/{10 × 5} × 100=76%$

Question : 3

If A exceeds B by 60% and B is less than C by 20%, then A : C is

a) 8 : 5

b) 4 : 5

c) 25 : 32

d) 32 : 25

Answer: (d)

Let C = 100; B = 80

A = ${80 × 160}/100 = 128$

A : C = 128 : 100 = 32 : 25

Question : 4

The ratio of the number of boys to that of girls in a school is 4 : 1. If 75% of boys and 70% of the girls are scholarship-holders, then the percentage of students who do not get scholarship is

a) 75%

b) 26%

c) 28%

d) 50%

Answer: (b)

Let the number of boys and girls be 4x and x respectively.

Number of boys who hold scholarship. = $75/100 × 4x = 3x$

and number of girls who hold scholarship = ${70 × x}/100 = {7x}/10$

Number of students who do not hold scholarship

= $5x - 3x - {7x}/10 = 2x - {7x}/10$

= ${20x - 7x}/10 = {13x}/10$

The required percentage = ${{13x}/10}/{5x} × 100$

= ${13x}/{10 × 5x} × 100 = 26$%

Question : 5

The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is

a) 54

b) 60

c) 36

d) 72

Answer: (d)

Boys in school = 2x

Girls = 3x

Students who are not scholarship holders :

Boys ⇒ ${2x × 75}/100 = {6x}/4$

Girls ⇒ ${3x × 70}/100 = {21x}/10$

Total students who donot hold scholarship = ${6x}/4 + {21x}/10$

= ${30x + 42x}/20 = {72x}/20 = {18x}/5$

Required percentage = ${{18x}/5}/{5x} ×100$ = 72%

Question : 6

If 15% of x is same as 20 % of y then x : y is

a) 6 : 5

b) 3 : 4

c) 5 : 4

d) 4 : 3

Answer: (d)

$x × 15/100 = y × 20/100$

x × 15 = y × 20

$x/y = 20/15 = 4/3$ = 4 : 3

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