model 11 percentage with ratios Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

Let the number of boys and girls be 4x and x respectively.

Number of boys who hold scholarship. = $75/100 × 4x = 3x$

and number of girls who hold scholarship = ${70 × x}/100 = {7x}/10$

Number of students who do not hold scholarship

= $5x - 3x - {7x}/10 = 2x - {7x}/10$

= ${20x - 7x}/10 = {13x}/10$

The required percentage = ${{13x}/10}/{5x} × 100$

= ${13x}/{10 × 5x} × 100 = 26$%

Answer: (d)

Let the numbers be 5x and 4x respectively

According to the question,

5x × $40/100$ = 12

2x = 12 ⇒ x = 6

4x of 50% = 4 × 6 × $1/2$ = 12

Answer: (c)

According to the question,

$x × 10/100 = 3 × y × 15/100$

10x = 45y

$x/y = 45/10 = 9/2$

Answer: (d)

$x × 15/100 = y × 20/100$

x × 15 = y × 20

$x/y = 20/15 = 4/3$ = 4 : 3

Answer: (b)

Let the first number be x and second number be y.

y - ${60x}/100 = {52y}/100$

100y – 60x = 52y

48y = 60x

$x/y = 48/60 = 4/5$ or 4 : 5

Answer: (a)

Let the number of boys and girls in the college be 3x and 2x respectively.

Number of minor boys = $3x × 80/100 = {12x}/5$

Number of minor girls = $2x × 75/100 = {3x}/2$

Total number of minor students = ${12x}/5 + {3x}/2$

= ${24x + 15x}/10 = {39x}/10 $

Required percentage = ${39x}/{10 × 5x} × 100$ = 78%

(As total students = 3x + 2x)