model 11 ratio & partnership Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

By the rule of alligation, CP of mixed tea

= $100/120 × 194.40$ = Rs.162 /kg

∴ Required ratio = $12/30 = 2/5$ or 2 : 5

Answer: (b)

Using Rule 1,

Let Cost price = 10x

Selling price = 11x

Gain per cent = ${11x - 10x}/{10x} × 100$

= $x/{10x} × 100 = 10%$

Answer: (d)

If the C.P. of the mixture be Rs.x per kg, then

$x = 120/100 = 32.40$

x = ${32.40 × 100}/120 = 27$

∴ Required ratio = 2 : 5

Answer: (b)

Share of rent = (number of oxen × time)

A : B : C = (10 × 7) : (12 × 5) : (15 × 30)

A : B : C = 70 : 60 : 45

A : B : C = 14 : 12 : 9

C’s share of rent = $9/{14 + 12 + 9} × 175$

= $9/35 × 175$ = 45

C’s share of rent is Rs.45

Answer: (b)

According to the question

$\text"Cost price"/ \text"Selling price" = 5/4$

Selling price = $4/5$ × Cost price

Loss = Cost price - Selling price

= Cost price - $4/5$ Cost price = $1/5$ Cost price

Loss % = ${{1/5}\text"Cost price" × 100}/\text"Cost price" = 100/5 = 20%$

Method 2 : Simple Approach

Rs.1 is loss on Rs.5.

loss % = $1/5$ × 100 = 20%

Here, C.P. = 5x, S.P. = 4x

Loss% = $\text"Loss"/ \text"C.P."$ × 100

= ${5x - 4x}/{5x}$ × 100 = 20%

Answer: (d)

Let x kg of sugar costing Rs.20/ kg and y kg of sugar costing Rs.15/kg are mixed.

According to the question,

20x + 15y = 16 (x + y)

20x + 15y = 16x + 16y

20x - 16x = 16y - 15y

4x = y ∴ $x/y = 1/4$ or 1 : 4

Method 2 :

By the rule of alligation,

∴ Required ratio = 1 : 4