Model 3 Opening both taps and leaks Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 3 EXERCISES
The following question based on pipes & cisterns topic of quantitative aptitude
(a) 17 hours
(b) 16 hours
(c) 14 hours
(d) 15 hours
The correct answers to the above question in:
Answer: (c)
Part of the cistern filled by pipes A, B and C in 1 hour = $1/6$
Part of the cistern filled by all three pipes in 2 hours = $1/3$
Remaining part =$1– 1/3 = 2/3$
Now, pipe A and B fill $2/3$ part of the cistern in 7 hours
Pipe A and B will fill the cistern in ${7 × 3}/2 = 21/2$ hours
Part of the cistern filled by Aand B in 1 hour = $2/21$
So Part of the cistern filled by C in 1 hour = $1/6 - 2/21$
= ${7 - 4}/42 = 1/14$
Pipe C will fill the cistern in 14 hours.
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Read more opening both taps and leaks Based Quantitative Aptitude Questions and Answers
Question : 1
A pipe can fill a tank with water in 3 hours. Due to leakage in bottom, it takes 3$1/2$ hours to fill it . In what time the leak will empty the fully filled tank ?
a) 10$1/2$ hours
b) 6$1/2$ hours
c) 12 hours
d) 21 hours
Answer »Answer: (d)
Using Rule 7,
Let the leak empty the full tank in x hours.
$1/3 - 1/x = 2/7$
$1/x = 1/3 - 2/7 = {7 - 6}/21$
$1/x = 1/21 ⇒ x = 21$ hours
Question : 2
A pump can fill a tank with water in 2 hours. Because of a leak in the tank it was taking 2$1/3$ hours to fill the tank. The leak can drain all the water off the tank in :
a) 14 hours
b) 4$1/3$ hours
c) 8 hours
d) 7 hours
Answer »Answer: (a)
Using Rule 7,A tap 'A' can fill a tank in 'x' hours and 'B' can empty the tank in 'y' hours. Then (a) time taken to fill the tankwhen both are opened = $({xy}/{x - y})$ : x > yb) time taken to empty the tankwhen both are opened = $({xy}/{y- x})$ : y > x
Work done in 1 hour by the filling pump = $1/2$
Work done in 1 hour by the leak and the filling pump = $3/7$
Work done by the leak in 1 hour
= $1/2 - 3/7 = {7 - 6}/14 = 1/14$
Hence, the leak can empty the tank in 14 hours.
Question : 3
Pipe A can fill a cistern in 6 hours and pipe B can fill it in 8 hours. Both the pipes are opened simultaneously, but after two hours, pipe A is closed. How many hours will B take to fill the remaining part of the cistern ?
a) 4 hrs
b) 2$2/3$ hrs
c) 2 hrs
d) 3$1/3$ hrs
Answer »Answer: (d)
Using Rule 1,
Part of the cistern filled in 2 hours by pipe A and B
= $2(1/6 + 1/8) =2({4 + 3}/24) = 7/12$
Remaining part =$1 - 7/12 = 5/12$
Time taken by pipe B in filling $5/12$ part
= $5/12 × 8 = 10/3 = 3{1}/3$ hours
GET pipes & cisterns PRACTICE TEST EXERCISES
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
pipes & cisterns Shortcuts and Techniques with Examples
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