Model 1 Basic Pipes & Cisterns problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 3 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on pipes & cisterns topic of quantitative aptitude

Questions : Pipe A can fill an empty tank in 6 hours and pipe B in 8 hours. If both the pipes are opened and after 2 hours pipe. A is closed, how much time B will take to fill the remaining tank?

(a) 3$1/3$ hours

(b) 7$1/2$ hours

(c) 2$2/5$ hours

(d) 2$1/3$ hours

The correct answers to the above question in:

Answer: (a)

Using Rule 1,

Part of tank filled by pipes A and B in 2 hours

= $2(1/6 + 1/8)$

=$2({4 + 3}/24) = 7/12$

Remaining part = $1 - 7/12 = 5/12$

This part is filled by pipe B.

Required time = $5/12$ × 8

= $10/3$ hours = 3$1/3$ hours

Practice pipes & cisterns (Model 1 Basic Pipes & Cisterns problems) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more basic pipes and cisterns problems Based Quantitative Aptitude Questions and Answers

Question : 1

Two pipes A and B can fill a tank in 20 minutes and 30 minutes respectively. If both pipes are opened together, the time taken to fill the tank is :

a) 15 minutes

b) 50 minutes

c) 12 minutes

d) 25 minutes

Answer: (c)

Part of the tank filled by both pipes in one minute

= $1/20 + 1/30$

Required time = $1/{1/20 + 1/30}$

= ${20 × 30}/50$ = 12 minutes

Using Rule 1,
Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?
Required time = $({xy}/{x + y})$ hrs

Here, x = 20, y = 30

Required time = $({xy}/{x + y})$ minutes

= $({20 × 30}/{20 + 30})$ minutes = 12 minutes.

Question : 2

One tap can fill a water tank in 40 minutes and another tap can make the filled tank empty in 60 minutes. If both the taps are open, in how many hours will the empty tank be filled ?

a) 3.5 hours

b) 2 hours

c) 2.5 hours

d) 3 hours

Answer: (b)

Using Rule 7,

Part of the tank filled when both taps are opened together

= $1/40 - 1/60 = {3 - 2}/120 = 1/120$

Hence, the tank will be filled in 120 minutes 2 hours.

Question : 3

Two pipes A and B can fill a cistern in 3 hours and 5 hours respectively. Pipe C can empty in 2 hours. If all the three pipes are open, in how many hours the cistern will be full?

a) 30 hours

b) can’t be filled

c) 10 hours

d) 15 hours

Answer: (a)

Using Rule 2,
If x, y, z, ........... all taps are opened together then, the time required to fill/empty the tank will be:
$1/x ± 1/y ± 1/z ± ... = 1/T$
Where T, is the required time
Note: Positive result shows that the tank is filling and Negative result shows that the tank is getting empty.

Part of cistern filled by three pipes in an hour

= $1/3 + 1/5 - 1/2 = {10 + 6 - 15}/30 = 1/30$

Hence, the cistern will be filled in 30 hours.

Question : 4

Two pipes A and B can separately fill a tank in 2 hours and 3 hours respectively. If both the pipes are opened simultaneously in the empty tank, then the tank will be filled in

a) 1 hour 20 minutes

b) 1 hour 12 minutes

c) 2 hours 30 minutes

d) 1 hour 15 minutes

Answer: (b)

Using Rule 1,

Part of tank filled by pipes A and B in 1 hour

= $1/2 + 1/3 = {3 + 2}/6 = 5/6$ parts

Required time = $6/5$ hours

= 1 hour $1/5$ × 60

= 1 hour 12 minutes

Question : 5

Three taps A, B, C can fill an overhead tank in 4, 6 and 12 hours respectively. How long would the three taps take to fill the tank if all of them are opened together ?

a) 5 hrs.

b) 2 hrs.

c) 4 hrs.

d) 3 hrs.

Answer: (b)

Using Rule 2,

Part of the tank filled by all three taps in an hour

= $1/4 + 1/6 + 1/12 = {6 + 4 + 2}/24 = 1 2$

Hence, the tank will be filled in 2 hours.

Question : 6

If two pipes function simultaneously, a tank is filled in 12 hours. One pipe fills the tank 10 hours faster than the other. How many hours does the faster pipe alone take to fill the tank?

a) 12 hrs

b) 20 hrs

c) 18 hrs

d) 15 hrs

Answer: (b)

Using Rule 1,

If the slower pipe fills the tank in x hours, then

$1/x + 1/{x - 10} = 1/12$

${x -10 + x}/{x(x - 10)} = 1/12$

$x^2 - 10x = 24x - 120$

$x^2 - 34x + 120$ = 0

$x^2 - 30x - 4x + 120$ = 0

$x (x - 30) - 4 (x - 30)$ = 0

$(x - 4) (x - 30)$ = 0

$x$ = 30 because $x ≠ 4$

Required time = 30 - 10 = 20 hours

Recently Added Subject & Categories For All Competitive Exams

Classification Reasoning MCQ For IBPS Clerk Prelims 2024

Most Important 100+ Classification based Verbal Reasoning Ability Multiple choice questions and answers PDF, Free New Mock tests For IBPS Clerk Prelims 2024

03-May-2024 by Careericons

Continue Reading »

Ratio and Proportion Questions with Solutions, IBPS Clerk

New Ratio and Proportion Quants Aptitude based Multiple Choice Questions and Answers Practice Test Series, Quiz & Mock Test for IBPS Clerk Prelims 2024 Exam

02-May-2024 by Careericons

Continue Reading »

Top Analogy Reasoning Ability For IBPS Clerk Prelims 2024

Most Important Analogy based Verbal Reasoning Multiple choice questions and answers practice quiz series PDF, Free New Mock tests For IBPS Clerk Prelims 2024

01-May-2024 by Careericons

Continue Reading »

SSC STENO: Mensuration Area & Volume Questions Test PDF

Free Mensuration Area and Volume Aptitude-based Practice multiple questions with solutions, Quiz, Full Mock Test & PDF for SSC Steno (Grade C & D) 2024 Exam

30-Apr-2024 by Careericons

Continue Reading »