model 10 percentage with allegations & mixture Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on percentage topic of quantitative aptitude
(a) 149 litres
(b) 155 litres
(c) 150 litres
(d) 150.4 litres
The correct answers to the above question in:
Answer: (c)
Glycerine in mixture = 40 litres
Water = 10 litres
Let x litres of pure glycerine is mixed with the mixture.
${40 + x}/{50 + x} = 95/100 = 19/20$
800 + 20x = 950 + 19x
x = 950 – 800 = 150 litres.
Discuss Form
Read more allegations mixture based Based Quantitative Aptitude Questions and Answers
Question : 1
A sugar solution of 3 litre contain 60% sugar. One liter of water is added to this solution. Then the percentage of sugar in the new solution is:
a) 60
b) 30
c) 45
d) 50
Answer »Answer: (c)
Quantity of sugar in the solution = ${3 × 60}/100 = 1.8$units
On adding 1 litre of water,
Required percent = $1.8/4 × 100 = 45%$
Question : 2
20 litres of a mixture contains 20% alcohol and the rest water. If 4 litres of water be mixed in it, the percentage of alcohol in the new mixture will be
a) 12$1/2$%
b) 33$1/3$%
c) 16$2/3$%
d) 25%
Answer »Answer: (c)
In 20 litres of mixture,
Alcohol = ${20 × 20}/100 = 4 litres$
Water = 20 - 4 = 16 litres
On adding 4 litres of water,
Quantity of water = 16 + 4 = 20 litres
Quantity of mixture = 24 litres
Required percent
=$4/24 × 100 = 50/3 = 16{2}/3%$
Question : 3
In one litre of a mixture of alcohol and water, water is 30%. The amount of alcohol that must be added to the mixture so that the part of water in the mixture becomes 15% is :
a) 900 ml
b) 1000 ml
c) 700 ml
d) 300 ml
Answer »Answer: (b)
In 1 litre i.e. 1000 ml of mixture,
Alcohol = 700 ml. Water = 300 ml.
Let x ml of alcohol is mixed.
$300/{1000 + x} ×100 = 15$
1000 + x = 2000 ⇒ x = 1000 ml.
Question : 4
A litre of pure alcohol is added to 6 litres of 30% alcohol solution. The percentage of water in the solution is
a) 40%
b) 50%
c) 65%
d) 60%
Answer »Answer: (d)
In 30% alcohol solution,
Alcohol = $30/100 × 6$ =1.8litres
Water = 4.2 litres
On mixing 1 litre of pure alcohol,
Percentage of water =$4.2/7 × 100$ = 60%
Question : 5
An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. To obtain 60 kg of pure iron, the quantity of the ore needed (in kgs) is approximately :
a) 300
b) 250.57
c) 266.67
d) 275.23
Answer »Answer: (c)
In 4 kg of ore, iron = 0.9 kg.
Quantity of ore for 60 kg of iron
= ${60 × 4}/0.9$ = 266.67 kg
Question : 6
In what ratio must a mixture of 30% alcohol strength be mixed with that of 50% alcohol strength so as to get a mixture of 45% alcohol strength ?
a) 3 : 1
b) 1 : 2
c) 1 : 3
d) 2 : 1
Answer »Answer: (c)
Let x litres of first mixture is mixed with y litres of the second mixture.
According to the question,
${x × 30 /100 + y × 50/100}/{x × 70/100 + y × 50/100} = 45/55$
${0.3x + 0.5y}/{0.7x + 0.5y} = 9/11$
6.3x + 4.5y = 3.3x + 5.5y
6.3x – 3.3x = 5.5y – 4.5y
3x = y ⇒ $x/y = 1 : 3$
GET percentage PRACTICE TEST EXERCISES
model 1 simple percentage questions
model 2 net increase or decrease in %
model 3 reducing & exceeding prices
model 4 x & y comparison
model 5 income & expenditure
model 6 consumption & remaining
model 7 marks scored in examinations
Model 8 population based
model 9 voters & election
model 10 percentage with allegations & mixture
model 11 percentage with ratios
percentage Shortcuts and Techniques with Examples
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model 1 simple percentage questions
Defination & Shortcuts … -
model 2 net increase or decrease in %
Defination & Shortcuts … -
model 3 reducing & exceeding prices
Defination & Shortcuts … -
model 4 x & y comparison
Defination & Shortcuts … -
model 5 income & expenditure
Defination & Shortcuts … -
model 6 consumption & remaining
Defination & Shortcuts … -
model 7 marks scored in examinations
Defination & Shortcuts … -
Model 8 population based
Defination & Shortcuts … -
model 9 voters & election
Defination & Shortcuts … -
model 10 percentage with allegations & mixture
Defination & Shortcuts … -
model 11 percentage with ratios
Defination & Shortcuts …
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