find distance only section 5 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Rohit drives his car from Bangalore towards Mysore. At a distance of 80 km, he turns right and proceeds for 50 km. Again he turns right and travels for 70 km. Finally he turns again towards right and travels for 50 km and stops there. How far is Rohit from Bangalore?

(a) 40 km

(b) 30 km

(c) 10 km

(d) 20 km

The correct answers to the above question in:

Answer: (c)

Mysore is to the south of Bangalore.

direction-and-distance-verbal-reasoning

Now, Rohit is 10km from Bangalore.

Practice direction & distance sense test (find distance only section 5) Online Quiz

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Read more type 2 section 5 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

Neha travelled from a point X straight to point Y at a distance of 50 meters. He turned to his right and walks 50 meter more, then again turned right and walks 60 meter. Finally, he turned to right and walks 50 meters. How far is he from the starting point?

a) 20

b) 30

c) 10

d) 40

e) None of these

Answer: (c)

Question : 2

Sanmitra walks 4 kms. towards north, turns right and walks 5 k.m. Then he turns towards south and walks 2 k.m. Again he takes a turn towards west walks 3 km and stops for a while. Then he further walks 2 km. What is the distance of Sanmitra from starting point ?

a) 2 k.m.

b) 3 k.m

c) 16 k.m.

d) 4 k.m.

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance = 2 km

Question : 3

Somu travelled from a point A straight to B, a distance of 12 km. He turned right and travelled 8 km and reached point C. From that point took right turn and travelled 6 km, and reached point D. How far is he away from the starting point ?

a) 12 km

b) 14 km

c) 10 km

d) 13 km

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= $√{8^2 + 6^2}$

= $√{64 + 36}$

= $√{100}$ = 10 km

Question : 4

Prakash travelled 6 km northward, then turned left and travelled 4 km, then turned left and travelled 6 km. How far was Prakash from the starting point?

a) 4 km

b) 8 km

c) 6 km

d) 10 km

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance = 4 km

DIRECTIONS:
  1. Point P is 5 m south of point A.
  2. Point T is 8 m east of point Q.
  3. Point Z is 4 m west of point V.
  4. Point P is 6 m west of point B.
  5. Point V is 6 m south of point T.
  6. Point Q is 4 m south of point B.

Question : 5

A person starts from point B in north direction. Walks for 6 m and reaches point C, takes a right turn walks for 5 m reaches point F. Again he takes a right turn, walks for 3 m, reaches point H, now takes a left turn, reaches point K, now takes a final right turn to reach point T. Find the area enclosed by points B, Q, T, K, H, F and C.

a) $65m^2$

b) $71m^2$

c) $58m^2$

d) $76m^2$

e) None of these

Answer: (b)

The area will be = Ar. of rectangle QCFD + Ar. of DHKT

= 10×5 + 3×7 = $71m^2$

Question : 6

Find distance AZ.

a) $6√13 m$

b) $4√14 m$

c) $5√13 m$

d) $7√15 m$

e) $3√11 m$

Answer: (c)

Vertical distance = 5+4+6 = 15 m

Horizontal distance = (PB) + (QT – CV) = 6 + (8-4) = 10 m

So AZ = $√ (15^2 + 10^2 ) = 5√13 m$

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