time and work Model Questions & Answers, Practice Test for ssc mts paper 1 2023

Answer: (b)

∵16 men can complete the work in 8 days.

∴ 1 man can complete the work in 8 × 16

∴ 12 men can complete the same work in

${16×8}/12={32}/3= 10 {2/3}$ days.

Answer: (a)

Let actual speed of train = $S_T$ km/h.

Then, $S_T - 6 = {75}/{18} × {18}/5$ = 15

⇒$S_T$ = 21 km/h

Now, let speed of second man = $S_m$

$21 - S_m = {75}/{15} × {18}/5$ = 15

⇒$S_m$ = 3 km/h

Answer: (a)

Part filled in 7 min. = 7 × $(1/36+1/45) = 7/20$

Remaining part = $(1-7/20) = 13/20$

Part filled by (A + B + C) in 1 min.

= $(1/36+1/45-1/30) = 1/60.$

Answer: (b)

Let C completes the work in x days.

Work done by (A + B) in 1 day = $1/10$

Work done by (B +C) in 1 day = $1/18$

A's 5 days' work + B's 10 days' work + C's 15 days' work = 1

or (A + B)'s 5 days' work + (B + C)'s 5 days' work + C's 10 days' work = 1

or $5/10+5/18+10/x=1$ or x = 45 days

Answer: (a)

Work done by A and B in 5 days = $(1/10+1/15)×5=5/6$

Work remaining = $1-5/6=1/6$

∴ C alone can do the work in 6 × 2 = 12 days

Ratio of their share work = $5/10:5/15:2/12=3:2:1$

Share of wages = Rs.225, Rs.150, Rs.75.