time and work Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Answer: (a)

Since, both trains are moving in opposite directions, so relative speed of one train with respect to the other

= 60 – (– 40) = 100 km/hr

∴ Time = ${150}/{100} = 3/2$ = hr..

Answer: (c)

$M_1D_1 = M_2D_2$

⇒(2M + 1W) × 14 = (4W + 2M) × 8

⇒28M + 14 W = 32 W + 16 M

⇒ 12M = 18

$M/W = {18}/{12} = 3/2$

Now, a man gets Rs.90 per day

∴ 1 woman wages = $2/3$ × (wages of 1 man)

= $2/3$ × 90 = Rs.60.

Answer: (c)

(A + B)'s 5 days' work = 5 $(1/25 + 1/20) = {45}/{100} = 9/{20}$

Remaining work = $(1-{9/20}) = {11}/{20}$

${11}/{20}$ of the work would be finished by B in ${{11}/{20}}/{1/20}$ = 11 days.

Answer: (c)

3 men + 4 boys = 8 days, 6 men + 8 boys = ?

By formula, $M_1D_1 = M_2D_2$

⇒(3M + 4B) × 8 = (6M + 8B) × $D_2$

⇒(3M + 4B) × 8 = 2(3M + 4B) ×' $D_2$

⇒ $D_2 = {(3M + 4B) × 8}/{2 × (3M + 4B)}$ = 4 days

Answer: (d)

From statement I

${M_1d_1}/{W_a_1} = {M_2d_2}/{W_a_2}$

Here $M_1 = 18, d_1 = 5 W_a_1$ = 1440

$M_2 = 10, d_2 = 6, W_2_a$ = ?

⇒ ${18 × 5}/{1440} = {10 × 6}/{W_a_2}$

⇒$W_a_2 = {10 × 6 × 1440}/{18 × 5}$ = Rs.960

But $Wa_2$ is given as 1280 so it is not correct.

From statement II

${M_1d_1}/{W_a_1} = {M_2d_2}/{W_a_2}$

Here $M_1 = 16, d_1 =7, W_a_1$ = 1120

$M_2 = 21, d_2 = 4, W_a_2$ = ?

⇒${16 × 7}/{1120}$

= ${21 × 4}/{W_a_2}$

$W_a_2 = {21 × 4 × 1120}/{16 × 7}$ = 3 × 280

= Rs. 840

Now, $W_a_2$ = Rs.800

So both statements are not correct.