number system Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Question :1

Three numbers which are co-prime to each other, are such that the product of the first two is 286 and that of the last two is 770. What is the sum of the three numbers?

Answer: (d)

Let numbers be a, b and c respectively

According to the question

a × b = 286

b × c = 770

Value of b is H.C.F of 286 and 770 = 22

∴ a = 13; b = 22; c = 35

a + b + c = 13 + 22 + 35 = 70

Question :2

Which one of the following statements is always correct?

Answer: (d)

It is always correct that the product of two square numbers is a square number.

e.g., 4 × 9 = 36

Question :3

If $√{x/y} = 10/3 - √{y/x}$ and x – y = 8, then the value of xy is equal to

Answer: (d)

$√{x/y} = 10/3 - √{y/x}$

$√{x/y} = 10/3 - 1/√{y/x}$

Let $√{x/y} = z$

∴ z = $10/3 - 1/z ⇒ 3z^2 - 10z + 3 = 0$

⇒ z = 3 or $1/3$

⇒ $√{x/y} = 3$ or $√{x/y} = 1/3$

⇒ x = 9y ...(i)

or 9x = y ...(ii)

But x – y = 8 ...(iii)

∴ x > y

Hence eq. (ii) is rejected

From eq. (i) and (iii),

9y – y = 8, ⇒ y = 1 and x = 9

∴ xy = 9 ´ 1 = 9

Question :4

The number 311311311311311311311 is

Answer: (d)

311 is repeated seven times in the number, 311 is not divisible by 3 but 311 repeated twice is not divisible by 3, but divisible by 11.

Similarly 311 repeated thrice is divisible by 3, but not by 11.

As 311 is repeated seven times, which is neither multiple of 2 nor 3.

So, number is not divisible by 3 or 11.

Question :5

A clock strickes once at 1 o’clock, twice at 2 o’clock and thrice at 3 o’clock and so on. If it takes 8 seconds to strike at 5 o’clock, the time taken by it to strike at 10 o’clock is

Answer: (a)

Time taken to reach 5'O Clock = 8 seconds

Time taken to reach 10'O Clock = $8/5$ seconds

Time taken to reach 10'O Clock

= $8/5 × 10$ =16 seconds

∴ Option (b) is correct.

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