mensuration Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Answer: (a)

Given, ratio of sides = 9 : 4

By properties of two similar triangle,

${\text"Area of first triangle"}/{\text"Area of second triangle"} = {(9)^2}/{(4)^2} = {81}/{16}$ or 81 : 16

Answer: (c)

Distance travel in 1 revolution = ${440}/{1000}$ m

and circumference = π × d = ${44000}/{1000}$ cm

∴ d = ${44000 × 7}/{1000 × 22}$ = 14 cm

Answer: (a)

Surface area of the cube = (6 × $8^2$) sq. ft. = 384 sq. ft.

Quantity of paint required = ${384}/{16}$ kg = 24 kg.

∴ Cost of painting = Rs.(36.50 × 24) = Rs.876.

Answer: (c)

Number of points is one, because circumcentre is the only point in the plane of a triangle, which is equidistant from the vertices of the triangle.

OA = OB = OC = r

Answer: (b)

Let the width of the rectangle = x unit

Therefore, Length = (2 x + 5) unit

According to the question,

Area = x (2x + 5) ⇒ 75 = $2x^2$ + 5x

⇒ $2x^2$ + 5x – 75 = 0

⇒ $2x^2$ + 15x – 10x – 75 = 0

⇒ x (2x + 15) – 5(2x + 15) = 0

⇒ (2x + 15) (x – 5) = 0

⇒ x = 5 and ${- 15}/2$

Since, width cannot be negative

∴ width = 5 units and length = 2x + 5

= 2 × 5 + 5 = 15 units

∴ Perimeter of the rectangle = 2 (15 + 5) = 40 units