mensuration Model Questions & Answers, Practice Test for ssc chsl tier 1 2024
ssc chsl tier 1 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Power, Indices And Surds
Time & Work
Time & Distance
Mensuration
In the figure given above. BC is parallel to DE and DE : BC = 3 : 5. What is the ratio of area of the Δ ABC to that of ΔDEA?
Answer: (d)
DE : BE = 3 : 5
∴ ${\text"Area of ΔABC"}/{\text"Area of ΔDAE"} = ({BC}/{DE})^2 = {25}/9$ or 25 : 9
A cone, a hemisphere and a cylinder stand on equal bases and have the same height, the height being equal to the radius of the circular base. Their total surface areas are in the ratio:
Answer: (b)
πr(r + l) : 3π $r^2$ : 2 π r (r + h)
= π × 1 (1 + $√2$) + : 3 × π × 1 : 2 × π × 1 (1 + 1)
= ($√2$ + 1) : 3: 4
The length and breadth of a rectangle are in the ratio 4:3. Then what is the ratio of the area of the triangle formed by the parts of the diagonals with a long side to the area of the triangle formed by the parts of diagonals with a short side?
Answer: (d)
Let length and breadth of a rectangle is 4x and 3x
Area of triangle BOC = ½×3x ×2x = $3x^2$
Area of triangle AOB = 1/2 × 4x ×1.5x = $3x^2$
∴ ratio = 1 : 1
Let ABCD be a parallelogram. Let P, Q, R and S be the mid-points of sides AB, BC, CD and, DA, respectively.
Consider the following statements.
I. Area of triangle APS < Area of triangle DSR, if BD < AC.
II. Area of triangle ABC = 4
[Area of triangle BPQ].
Select the correct answer using the codes given below.
Answer: (c)
Area of ΔAPS = Area of ΔDSR
∵ AS = SD and AP = DR
∴ ar (ΔABC)= 4ar (ΔBPQ)
The sides of a right angled triangle are equal to three consecutive numbers expressed in centimeters. What can be the area of such a triangle?
Answer: (b)
In right angle triangle, the sides of triangle are three consecutive number then AB = 4 cm, BC = 3 cm, AC = 5 cm
∴ Area of triangle, $1/2 × 3 × 4 = 6 cm^2$
ssc chsl tier 1 2024 IMPORTANT QUESTION AND ANSWERS
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