averages Model Questions & Answers, Practice Test for ssc cgl tier 1
ssc cgl tier 1 SYLLABUS WISE SUBJECTS MCQs
Computation of whole numbers, decimals, fractions and relationships between numbers
Percentage
Averages
The average monthly rainfall for a year in Guntur district is 2.7 inches, the average for the first 7 months is 1.1 inches less than the annual average. If the total rainfall for the next 4 months is 20.8 inches, then the rainfall in the last month will be
Answer: (a)
Total annual rainfall = 2.7 × 12 = 32.4 inches
Rainfall for first seven months = (2.7 – 1.1) × 7 = 11.2
Total for first 11 months = 11.2 + 20.8 = 32 inches
Rainfall for last month = 32.4 – 32 = 0.4 inches
14-17. You have to take between 25th and 30th to mean that both these dates are also included.
Find the average of the following set of scores: 178, 863, 441, 626, 205, 349, 462, 820
Answer: (d)
Required average
= ${178 + 863 + 441 + 626 + 205 + 349 + 462 + 820}/8$
= $3944/8$ = 493
Out of three given numbers, the first number is twice the second and thrice the third. If the average of the three numbers is 154, what is the difference between the first and the third number?
Answer: (e)
Let the first number be = 6x
∴ Second number = 3x
and the third number = 2x
According to the question,
6x + 3x + 2x = 154 × 3
or, 11x = 154 × 3
∴ $x = {154 × 3}/11 = 42$
∴ Required difference = 6x – 2x = 4x = 4 × 42 = 168
A batsman scores 80 runs in his sixth innings and thus increases his average by 5. What is his average after six innings?
Answer: (a)
Let the average of 5 innings = x
Scores in sixth inning = 80
∴ Total of 5 innings = 5x
According to the question,
${5x + 80}/6 = x + 5$
⇒ 5x + 80 = 6x + 30
⇒ x = 80 – 30 = 50
∴ His average after six innings = 50 + 5 = 55
In a family, a couple has a son and daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is nine years younger to her husband and the brother is seven years older than his sister. What is the age of the mother?
Answer: (d)
Let the mother's age be y years.
∴ The age of father = (y + 9) years
The age of son = $y/2$ years
The age of daughter = $(y/2 - 7)$ years
Now according to the given condition,
(y + 9) = 3$(y/2 - 7)$
⇒ y + 9 = ${3y - 42}/2$
⇒ 2y + 18 = 3y – 42
⇒ y = 60 years
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