percentage Model Questions & Answers, Practice Test for ssc cgl tier 1

Question :1

In an examination it is required to get 296 of the total maximum aggregate marks to pass. A student gets 259 marks and is declared failed. The difference of marks obtained by the student and that required to pass is 5%. What are the maximum aggregate marks a student can get?

Answer: (c)

According to the question,

5% of max. marks = 296 – 259

∴ Max. marks = $3700/5$ = 740

Question :2

570 % of ? = 377910

Answer: (a)

? × $570/100$ = 377910

or ? = ${377910 × 100}/570$ = 66300

Question :3

In an election between two candidates, 75% of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of total valid votes. Find the total number of votes enrolled in that election.

Answer: (a)

Let the total number of votes enrolled be x.

Then, Number of votes cast = 75% of x. Valid votes = 98% of (75% of x).

∴ 75% of [98% of (75% of x)] = 9261

$(75/100 × 98/100 × 75/100 × x)$ = 9261

$x = ({9261 × 100 × 100 × 100}/{75 × 98 × 75})$ = 16800.

Question :4

A obtains 33$1/3$ % of the marks in a paper for which the maximum was 300. B is ahead of A by 40% of A’s marks, while C is ahead of B by two-ninths of his own marks. How many marks does C get?

Answer: (b)

A's marks = $300 × {33{1}/3}/100$ = 100.

B's marks = 100 × (1 + 40/100) = 140.

C is ahead of B by 2/9 of his own marks

i.e. 7/9 of C's marks = 140

C's marks = 140 × 9/7 = 180.

Question :5

45% of a number is 255.6. What is 25% of that number?

Answer: (d)

According to the question,

∴ Number × $45/100 = 255.6$

or Number = $255.6 × 20/9$ = 568

∴ 25% of number = x × $25/100$

= 568 × $25/100$ = 142

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