linear equations Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

Answer: (b)

Statement 1

1990x – 173y = 11

x = 0, $y = {- 11}/{173}, x = 1, y = {1990 - 11}/{173}$ = 11.43

y = 0, x = ${11}/{1990} y = 1, x = {11 + 173}/{1990}$ = 0.0924

This equation has no integers solution for any value of x and y.

Statement 2

3x – 12y = 7

x = 0, y = ${-7}/{12}$ = -0.5833, x = 1, y = -0.333

y = 0, x = $7/3$= 2.33 y = 1, x = 6.33.

So statement 1 and statement 2 both are correct.

Answer: (c)

H + G = 81 ...(1)

2H + 4G = 234

or H + 2G = 117 ...(2)

(2) – (1)⇒G = 36

Answer: (b)

Let the number be y.

∴ $y/3 = y/4$ = + 8

⇒${4y – 3y}/{12}$ = 8

⇒ = 12 × 8 = 96

∴ Sum of digits = 9 + 6 = 15

Answer: (a)

Let the number of column be x.

Number of rows = x + 4

According to the question,

x(x + 4) × 5 – 2 = 158

⇒ 5x(x + 4) = 160

⇒ x(x + 4) = 32

⇒ $x^2$ + 4x – 32 = 0

⇒ $x^2$ + 8x – 4x – 32 = 0

⇒ x(x + 8) – 4(x + 8) = 0

⇒ (x + 8) (x – 4) = 0

So, x = 4 as x = –8 is not possible

∴ Number of rows = x + 4 = 4 + 4 = 8

Answer: (b)

Clearly, the required number would be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5. Such a number is 25.