average Model Questions & Answers, Practice Test for ibps so prelims

Answer: (c)

Let Seema's present age be x years.

Then, Seema's son's present age = $x/4$ years

Seema's father's present age = ${7x}/4$ years.

Then, $x + x/4 + {7x}/4 = 32 × 3$

12x = 96 × 4

$x = {96 × 4}/12 = 32$

∴ Required difference = ${7 × 32}/4 - 32/4$

= 56 – 8 = 48 years

Answer: (d)

Let the five consecutive even numbers be

x, x + 2, x + 4, x + 6 and x + 8 respectively.

According to the question,

x + x + 2 + x + 4 + x + 6 + x + 8 = 5 × 52

or 5x + 20 = 260

or 5x = 260 – 20

or $x = 240/5$ = 48

∴ B = x + 2 = 48 + 2 = 50 and

E = x + 8 = 48 + 8 = 56

∴ B × E = 50 × 56 = 2800

Answer: (a)

D's weight = 4 × 80 – 3 × 84 = 320 – 252 = 68.

E's weight = 68 + 3 = 71.

Now, we know that A + B + C + D = 4 × 80 = 320 and

B + C + D + E = 78 × 4 = 312.

Hence, A's weight is 8 kg more than E's weight.

A = 71 + 8 = 79.

Answer: (d)

Let the numbers are x, y and z.

Then, $({x + y}/2) - ({y + z}/2)$ = 15

or (x + y) – (y + z) = 30

or x – z = 30

Answer: (d)

a + b + c + d + e = 5 × 92 = 460

a + b + c = 3 × 83 = 249

c + d + e = 3 × 97 = 291

∴ c = (a + b + c) + (c + d + e) – (a + b + c + d + e)

or c = 540 – 460 or c = 80