simple and compound interest Model Questions & Answers, Practice Test for ibps po prelims 2023

Question :1

Ms. Maya deposits an amount of Rs. 17,800 and obtained Rs. 31,684 at the end of 6 years. What was the rate of simple interest per year?

Answer: (d)

Rate of Interest = ${(31684-17800)×100}/{17800×6}$%

= $1388400/106800$ =13%

Question :2

Amount of S.I. accrued on an amount of Rs. 28,500 in seven years is Rs. 23940. What is the rate of interest per annum?

Answer: (d)

Rate of interest = ${\text"\text"S.I""×100}/\text"P×T"={23940×100}/{28500×7}$

= 12% p.a.

Question :3

A merchant commences with a certain capital and gains annually at the rate of 25 p.c. At the end of 3 years he has Rs. 10,000. What was his original capital ?

Answer: (c)

10000 = x $(1 + {{25}/{100}})^3$

∴ ${10000 × 4 × 4 × 4}/{5 × 5 × 5}$ = Rs. 5120

Question :4

The simple interest accrued on a sum of certain principal is Rs. 2000 in five years at the rate of 4% per annum. What would be the compound interest accrued on same principal at same rate in two years ?

Answer: (d)

2000 = ${P × 4 × 5}/100$

∴P = 10000

Now, CI = 10000$[(1+{4/{100}})^2 -1]$ = 10000 × 0.0816 = 816

Question :5

A father divides Rs. 5100 between his two sons, Mohan and Sohan who are 23 and 24 at present in such a way that if their shares are invested at compound interest @ 4% p.a., they will receive equal amount on attaining the age of 26 years. Mohan’s share is

Answer: (b)

(1 + r) = $1+1/25=26/25$

Let Mohan and Sohan receives Rs. x and Rs. y respectively at present.

Then $x/y=(26/25)^{2-3}=(26/25)^{-1}=25/26$

∴ Mohan's share = $25/51$ × Rs. 5100 = Rs. 2500

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