Model 1 Train Vs Train in same direction Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 4 p.m.
(b) 4.30 p.m.
(c) 6 p.m.
(d) 5 p.m.
The correct answers to the above question in:
Answer: (a)
Distance covered by the thief in half an hour
= $1/2 × 40$ = 20 km
Relative speed of car owner
= 50 – 40 = 10 km
Required time
= $\text"Difference of distance"/ \text"Relative speed"$
= $20/10$ = 2 hours
i.e. at 4 p.m.
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Read more trains in same direction Based Quantitative Aptitude Questions and Answers
Question : 1
Two trains start from a certain place on two parallel tracks in the same direction. The speed of the trains are 45 km/hr and 40 km/ hr respectively. The distance between the two trains after 45 minutes will be
a) 2 km 750 m
b) 3 km 750 m
c) 3 km 250 m
d) 2 km 500 m
Answer »Answer: (b)
Relative speed
= 45– 40 = 5 kmph
Required distance
= $(5 × 45/60)$ km
= $15/4$ km = 3 km 750
Question : 2
A policeman goes after a thief who has 100 metres start, if the policeman runs a kilometre in 8 min, and the thief a km in 10 min, the distance covered by thief before he is over-powered is
a) 400 m
b) 320 m
c) 420 m
d) 350 m
Answer »Answer: (a)
Relative speed
= $1000/8 – 1000/10$
= ${5000 – 4000}/40 = 1000/40$ m/minute
Required time
= $100/{1000/40} = 4000/1000$ = 4 m/minute
Distance covered by the thief
= $1000/10 × 4 = 400$ metres
Question : 3
How much time does a train, 50 m long, moving at 68 km/ hour take to pass another train, 75 m long, moving at 50 km/ hour in the same direction ?
a) 10 seconds
b) 20 seconds
c) 25 seconds
d) 5 seconds
Answer »Answer: (c)
Both trains are moving in the same direction.
Their relative speed
= (68 – 50) kmph = 18 kmph
= 18 × $5/8$ = 5 m/sec
Total length
= 50 + 75 = 125 m
Required time
= $\text"Total length"/ \text"Relative speed"$
= $125/5$ = 25 seconds.
Question : 4
Two trains of equal length are running on parallel lines in the same direction at 46 km/hour and 36 km/hour. The faster train passes the slower train in 36 seconds. The length of each train is
a) 80 m
b) 82 m
c) 50 m
d) 72 m
Answer »Answer: (c)
Let the length of each train be x metre.
Relative speed
= (46 – 36) kmph = 10 kmph
= $({10 × 5}/18)$ m./sec.
= $25/9$ m./sec.
${2x}/{25/9} = 36$
$2x = 36 × 25/9$ = 100
$x = 100/2$ = 50 metre
Question : 5
Two trains start from stations A and B and travel towards each other at speeds of 50 kmph and 60 kmph respectively. At the time of their meeting, the second train has travelled 120 km more than the first. The distance between A and B is
a) 1440 km
b) 1320 km
c) 990 km
d) 1200 km
Answer »Answer: (b)
Let both trains meet after t hours.
Distance = speed × time
60t – 50t = 120
10t = 120 ⇒ t = 12 hours
Required distance
= 60t + 50t
= 110t = 110 × 12 = 1320 km
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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