Model 3 Train Vs Bridge/Platform Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 500 metres
(b) 750 metres
(c) 1250 metres
(d) 1000 metres
The correct answers to the above question in:
Answer: (c)
Using Rule 10,
Time = 5 minutes = $1/12$ hour
Length of bridge = Speed × Time
= 15 × $1/12 = 5/4$ km.
= $(5/4 × 1000)$ metre
= 1250 metre
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Read more crossing bridge platform Based Quantitative Aptitude Questions and Answers
Question : 1
A train 800 metres long is running at the speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in metres) is :
a) 500
b) 1300
c) 13
d) 77200
Answer »Answer: (a)
When a train crosses a tunnel, it covers a distance equal to the sum of its own length and tunnel.
Let the length of tunnel be x Speed = 78 kmph
= ${78 × 1000}/{60 × 60}$ m/sec. = $65/3$ m/sec.
Speed = $\text"Distance"/\text"Time"$
$65/3 = {800 + x}/60$
(800 + x ) × 3 = 65× 60
800 + x = 65 × 20 m
x = 1300 - 800 = 500
Length of tunnel = 500 metres.
Using Rule 10,
Here, x = 800 m, u = 78 km/hr
= 78$5/18 = 65/3$ m/sec
t = 1 min = 60 sec, y = ?
using t = ${x + y}/u$
$60 = {800 + y}/{65/3}$
60 × $65/3$ = 800 + y
1300 - 800 = y ⇒ y = 500 metres
Question : 2
How many seconds will a train 120 metre long running at the rate of 36 km/hr take to cross a bridge of 360 metres in length ?
a) 40 sec
b) 46 sec
c) 36 sec
d) 48 sec
Answer »Answer: (d)
Using Rule 10,
Speed of train = 36 kmph
= $({36 × 5}/18)$ m/sec.
= 10 m/sec
Required time
= $\text"Length of train and bridge"/ \text"Speedof train"$
= ${120 + 360}/10$
= $480/10$ = 48 seconds
Question : 3
A train travelling with uniform speed crosses two bridges of lengths 300 m and 240 m in 21 seconds and 18 seconds respectively. The speed of the train is :
a) 68 km/hr
b) 65 km/hr
c) 60 km/hr
d) 72 km/hr
Answer »Answer: (d)
Using Rule 10,
Let the length of the train be x
Speed of train
${x + 300}/21 ={x + 240}/18$
${x + 300}/7 ={x + 240}/6$
7x + 1680 = 6x + 1800
x = 120
Speed of train
= ${x + 300}/21 = 420/21$= 20 m/sec
= $({20 × 18}/5)$ kmph = 72 kmph
Question : 4
A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is
a) 85 ft/second
b) 100 ft/second
c) 120 ft/second
d) 70 ft/second
Answer »Answer: (c)
Speed of train
= $\text"Lengthof(train + platform)"/ \text"Timetaken tocross"$
= $({500 + 700}/10)$ feet/second
= 120 feet/second
Using Rule 10,
Here, x = 500 feet, y = 700 feet
t = 10 seconds, u = ?
using t = ${x + y}/u$
u = ${500 + 700}/10$
= 120ft/second
Question : 5
A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is
a) 10
b) 15
c) 20
d) 50
Answer »Answer: (b)
Using Rule 10,If a train of length x m crosses a platform/tunnel/bridge of length y m with the speed u m/s in t seconds, then,t = ${x + y}/u$
Speed of train
= $\text"Length of (train + platform)"/ \text"Time taken in crossing"$
= ${(50 + 100)}/10 = 150/10$ = 15 m/sec
Question : 6
A moving train passes a platform 50 metre long in 14 seconds and a lamp post in 10 seconds. The speed of the train (in km/h) is :
a) 36
b) 40
c) 45
d) 24
Answer »Answer: (c)
Let the length of train be x metre.
When a train crosses a platform, distance covered by it
= length of train and platform.
Speed of train
= ${x + 50}/14 = x/10$
${x + 50}/7 = x/5$
7x = 5x + 250
7x - 5x = 250
2x = 250 ⇒ x = $250/2$ = 125 metre
Speed of train = $x/10$
= $(125/10)$ m./sec.
= $(125/10 × 18/5)$ kmph = 45 kmph.
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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