model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : A tradesman marks his goods at such a price that after allowing a discount of 15%, he makes a profit of 20%. What is the marked price of an article whose cost price is Rs.170 ?

(a) Rs.200

(b) Rs.220

(c) Rs.240

(d) Rs.260

The correct answers to the above question in:

Answer: (c)

If the marked price be x, then

$x × 85/100 = {170 × 120}/100$

x × 85 = 170 × 120

$x = {170 × 120}/85$ = Rs.240

Using Rule 6,

Here, D = 15% r = 20%

C.P. = Rs.170

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$\text"MP"/170 = {100 + 20}/{100 - 15}$

$\text"M.P."/170 = 120/85$

M.P. = ${120 × 170}/85$

M.P. = Rs.240

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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers

Question : 1

The marked price of a radio is Rs.480. The shopkeeper allows a discount of 10% and gains 8%. If no discount is allowed, his gain percent would be

a) 20%

b) 20.5%

c) 18%

d) 18.5%

Answer: (a)

If the CP of radio be x, then

$108/100 of x = {480 × 90}/100$

${x × 108}/100$ = 432

$x = {432 × 100}/108$ = Rs.400

Gain per cent (if no discount is allowed)

= $80/400 × 100$ = 20%

Using Rule 6,

Here, r = 8%, D = 10%, M.P. = Rs.480

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$480/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${480 × 90}/108$ = Rs.400

Gain % = $\text"S.P. - C.P."/\text"C.P." × 100$

(without discount)

= ${480 - 400}/400 × 100$

= $80/400 × 100$ = 20%

Question : 2

How much percent above the cost price should a shopkeeper mark his goods so as to earn a profit of 32% after allowing a discount of 12% on the marked price ?

a) 45%

b) 60%

c) 50%

d) 40%

Answer: (c)

Let the C.P. be 100 and the marked price be x.

$x × 88/100$ = 132

$x = {132 × 100}/88$ = 150

i.e., more by 50%

Using Rule 9,
The marked price of an article is fixed in such a way that after allowing a discount of r% a profit of R% is obtained. Then the marked price of the article is $({r + R}/{100 - r} × 100)$% more than its cost price.

Here, r = 12% R = 32%

Required percentage

= $({r + R}/{100 - r} × 100)$%

= $({12 × 32}/{100 - 12}) × 100%$

= $44/88 × 100$ = 50%

Question : 3

The marked price of an electric iron is Rs.300. The shopkeeper allows a discount of 12% and still gains 10%. If no discount is allowed, his gain per cent would have been :

a) 30%

b) 27%

c) 20%

d) 25%

Answer: (d)

SP of electric iron

= 88% of 300

= Rs.${300 × 88}/100$ = Rs.264

Profit = 10%

CP of electric iron

= $100/110 × 264$ = Rs.240

After no discount,

Gain = 300 - 240 = Rs.60

Gain per cent

= $60/240$ × 100 = 25%

Using Rule 6,

Here, M.P. = Rs.300, r = 10%, D = 12%.

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$300/\text"CP" = {100 + 10}/{100 - 12}$

C.P. = ${300 × 88}/110$

Gain % (without discount)

= ${300 - 240}/240 × 100$ = 25%

Question : 4

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs.880, is

a) Rs.680

b) Rs.774

c) Rs.704

d) Rs.640

Answer: (d)

SP of article

= (100 - 20)% of 880

= 80%of 880

= 880 × $80/100$ = Rs.704

Let CP be x

Again, 110% of x = 704

x = $704/110 × 100$ = Rs.640

Original cost = Rs.640

Using Rule 6,

Here, r = 10%, D = 20%, M.P. = Rs.880, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$880/\text"C.P." = {100 + 10}/{100 - 20}$

C.P. = ${880 × 80}/110$

C.P. = Rs.640

Question : 5

After allowing a discount of 16%, there was still a gain of 5%. Then the percentage of marked price over the cost price is

a) 25%

b) 21%

c) 15%

d) 18%

Answer: (a)

Let the C.P. of article be Rs.100 and its marked price be x.

$x × 84/100 = 105$

$x = {105 × 100}/84 = 125$

Required percentage = 25%

Using Rule 6,

Here, r = 5% D = 16%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

= ${100 + 5}/{100 - 16} = 105/84$

Required Percentage

= ${105 - 84}/84 × 100$ = 25%

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