model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) Rs.600
(b) Rs.700
(c) Rs.900
(d) Rs.800
The correct answers to the above question in:
Answer: (a)
S.P. of that article
= 800 × $90/100$ = Rs.720
He still makes 20% profit
C.P. of the article
= 720 $×100/120$ = Rs.600
Using Rule 6,If r% of profit or loss occur after giving D% discount on marked price, then$\text"MP"/\text"CP" = {100 ± r}/{100 - D}$(positive sign for profit and negative for loss)
Here, r = 20%, D = 10%, M.P. = Rs.800, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$800/\text"CP" = {100 + 20}/{100 - 10}$
C.P. = ${800 × 90}/120$
C.P. = Rs.600
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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers
Question : 1
A trader allows a trade discount of 20% and a cash discount of 6$1/4$% on the marked price of the goods and gets a net gain of 20% of the cost. By how much above the cost should the goods be marked for the sale ?
a) 70%
b) 60%
c) 40%
d) 50%
Answer »Answer: (b)
Let C.P. of article = Rs.100
Marked price = x
Single equivalent discount
= $(20 + {25/4} - {20 × 25}/400)$% = 25%
$x × 75/100$ = 120
$x = {120 × 100}/75$ = Rs.160
160 - 100 = 60%
Question : 2
Marked price of an article is Rs.275. Shopkeeper allows a discount of 5% and he gets a profit of 4.5%. The actual cost of the article is
a) Rs.210
b) Rs.215
c) Rs.250
d) Rs.225
Answer »Answer: (c)
Let C.P. of article be x
${x × 104.5}/100 = {275 × 95}/100$
x × 104.5 = 275 × 95
$x = {275 × 95}/{104.5}$ = Rs.250
Using Rule 6,
M.P. = Rs.275, D = 5%,
r = 4.5%, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$275/\text"C.P." = {100 + 4.5}/{100 - 5}$
C.P. = ${275 × 95}/{104.5}$
C.P. = Rs.250
Question : 3
After allowing a discount of 16%, there was still a gain of 5%. Then the percentage of marked price over the cost price is
a) 25%
b) 21%
c) 15%
d) 18%
Answer »Answer: (a)
Let the C.P. of article be Rs.100 and its marked price be x.
$x × 84/100 = 105$
$x = {105 × 100}/84 = 125$
Required percentage = 25%
Using Rule 6,
Here, r = 5% D = 16%
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
= ${100 + 5}/{100 - 16} = 105/84$
Required Percentage
= ${105 - 84}/84 × 100$ = 25%
Question : 4
A grinder was marked at Rs.3,600. After given a discount of 10% the dealer made a profit of 8%. Calculate the cost price.
a) Rs.2,960
b) Rs.3,240
c) Rs.3,000
d) Rs.3,312
Answer »Answer: (c)
If the C.P. of grinder be x, then
${x × 108}/100 = {3600 × 90}/100$ = 3240
$x = {3240 × 100}/108$ = Rs.3000
Using Rule 6,
M.P. = Rs.3600, D = 10%,
r = 8%, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$3600/\text"CP" = {100 + 8}/{100 - 10}$
C.P. = ${3600 × 90}/108$
= ${3600 × 10}/12$ = Rs.3000
Question : 5
A shopkeeper marks his goods 40% above the cost price. He allows a discount of 5% for cash payment to his customers. He receives Rs.1064 after paying the discount. His profit is
a) Rs.800
b) Rs.200
c) Rs.264
d) Rs.164
Answer »Answer: (a)
Cost price of article = Rs.x
$x × 140/100 × 95/100 = 1064$
$x = {1064 × 100 × 100}/{140 × 95}$ = Rs.800
Question : 6
A manufacturer marked an article at Rs.50 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was
a) Rs.30
b) Rs.32
c) Rs.40
d) Rs.35
Answer »Answer: (b)
Marked price = Rs.50
S.P. after discount = 80% of 50 = Rs.40
If the CP of article be x, then
${125 × x}/100 = 40$
$x = {40 × 100}/125$ = Rs.32
Using Rule 6,
Here, M.P. = Rs.50, C.P. = ?,
r = 25%, D = 20%
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$50/\text"CP" = {100 + 25}/{100 - 20}$
C.P.= ${50 × 80}/125$ = Rs.32
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
discount Shortcuts and Techniques with Examples
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