model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 1 year
(b) 9 months
(c) 10 months
(d) 8 months
The correct answers to the above question in:
Answer: (d)
Present worth
= 1860 - 60 = Rs.1800
Time = ${100 × \text"True Discount"}/\text"Present worth × Rate"$
= ${100 × 60}/{1800 × 5} = 2/3$ year
= $(2/3 × 12)$ months = 8 months
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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers
Question : 1
After allowing a discount of 12% on the marked price, a shopkeeper still gains 21%. The marked price is above the cost price by
a) 42.5%
b) 37.5%
c) 25%
d) 30%
Answer »Answer: (b)
C.P. of article = Rs.100
Marked price be x
${x × 88}/100$ = 121
$x = {121 × 100}/88$ = Rs.137.5
i.e. 37.5% above C.P.
Using Rule 9,
Here, r = 12%, R = 21%
Required percentage
= $({r + R}/{100 - r} × 100)$%
= $({12 + 21}/{100 - 12}) × 100%$
= $33/88 × 100%$
= $3/8 × 100$
= $300/8$% = 37.5%
Question : 2
A shopkeeper earns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is
a) 47 : 51
b) 47 : 56
c) 45 : 56
d) 45 : 51
Answer »Answer: (c)
Let the CP be Rs.100.
SP = Rs.112
If the marked price be x, then
90 % of x = 112
x = ${112 × 100}/90$ = Rs.$1120/9$
Required ratio = 100 : $1120/9$
= 900 : 1120 = 45 : 56
Using Rule 6,
Here, r = 12% D = 10%
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$\text"MP"/\text"CP" = {100 + 12}/{100 - 10}$
$\text"MP"/\text"CP" = 112/90$
$\text"CP"/\text"MP" = 90/112$
$\text"CP"/\text"MP" = 45/56$
C.P. : M.P. = 45 : 56
Question : 3
A trader wishes to gain 20% after allowing 10% discount on the marked price to his customers. At what per cent higher than the cost price must he marks his goods ?
a) 35%
b) 34$2/3$%
c) 30%
d) 33$1/3$%
Answer »Answer: (d)
Let the CP be Rs.100.
Then SP = Rs.120
Let the marked price be x.
Then, 90% of x = Rs.120
$x = {120 × 100}/90$
= $400/3 = 133{1}/3$
It is $33{1}/3$% higher than the CP.
Question : 4
A shopkeeper buys an article for Rs.180. He wishes to gain 20% after allowing a discount of 10% on the marked price to the customer. The marked price will be
a) Rs.300
b) Rs.270
c) Rs.210
d) Rs.240
Answer »Answer: (d)
SP = $180 × 120/100$ = Rs.216
90% = 216
100% = $216/90 × 100$ = Rs.240
Question : 5
The cost of manufacturing an article was Rs.900. The trader wants to gain 25% after giving a discount of 10%. The marked price must be :
a) Rs.1000
b) Rs.1200
c) Rs.1500
d) Rs.1250
Answer »Answer: (d)
CP = Rs.900
S.P. = 125% of 900
= $({900 × 125}/100)$ = Rs.1125
Let the marked price be x
90% of x = Rs.1125
$x = {1125 × 100}/90$ = Rs.1250
Question : 6
A trader sells his goods at a discount of 20%. He still makes a profit of 25%. If he sells the goods at the marked price only, his profit will be
a) 54.25%
b) 50.25%
c) 56.25%
d) 25.56%
Answer »Answer: (c)
Let the marked price = Rs.100
S.P = Rs.80
Profit = 25%
CP = Rs.$(100/125 × 80)$ = Rs.64
Profit after selling on marked price
= 100 - 64 = Rs.36
Gain % = $36/64 × 100$ = 56.25%
Using Rule 6,
Here, D = 20% r = 25%
Let, M.P. be Rs.100
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$100/\text"CP" = {100 + 25}/{100 - 20}$
C.P. = ${100 × 80}/125$
C.P. = Rs.64
Profit = 100 - 64 = 36
Gain % = $36/64 × 100%$ = 56.25%
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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