model 2 hiking & discounting Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 12%
(b) 17%
(c) 14%
(d) 15%
The correct answers to the above question in:
Answer: (c)
Let C.P. be Rs.100.
Marked price = Rs.120
S.P. = ${120 × 95}/100$ = Rs.114
Gain per cent = 14%
Using Rule 8,
Here, r = 20%, $r_1$ = 5%
Gain % = ${r × (100 - r_1)}/100 - r_1$
= ${20 × (100 - 5)}/100 - 5$
= 19 - 5 = 14%
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Question : 1
A shopkeeper marks the price of an item keeping 20% profit. If he offers a discount of 12$1/2$% on the marked price, his gain percent will be
a) 5%
b) 8%
c) 7.5%
d) 4.5%
Answer »Answer: (a)
Let the cost price be Rs.100.
Marked price = Rs.120
SP = 87$1/2$% of 120
= $175/200 × 120$ = Rs.105
Gain per cent = 5%
Using Rule 8,
Here, r = 20%, $r_1 = 12{1}/2$%
Profit % = ${r × (100 - r_1)}/100 - r_1$
= ${20 × (100 - {25/2})}/100 - {25/2}$
= ${20 × 175}/200$ - 12.5
= 17.5 - 12.5 = 5%
Question : 2
A tradesman marks his goods 10% above his cost price. If he allows his customers 10% discount on the marked price, how much profit or loss does he make, if any?
a) 1%loss
b) No gain, no loss
c) 5% gain
d) 1% gain
Answer »Answer: (a)
Required loss [As per Rule]
= $({10 × 10}/100)$% = 1%
Using Rule 8,A tradesman marks his goods r% above his cost price. If he allows his customers a discount of $r_1$% on the marked price. Then is profit or loss per cent is${r × (100 - r_1)}/100 - r_1$(Positive sign signifies profit and negative sign signifies loss).
Here, r = 10% and $r_1$ = 10%
Required profit or loss
= ${r × (100 - r_1)}/100 - r_1$
= ${10 × (100 - 10)}/100 - 10$
= 9 - 10
= –1% (–ve sign shows loss) = 1% loss
Question : 3
A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed the discount of :
a) 10%
b) 10.5%
c) 9%
d) 11%
Answer »Answer: (a)
Let C.P. be 100
Marked price = 110
x% of 110 = 11
x = ${11 × 100}/110$ = 10%
Using Rule 8,
Here, loss % = 1%, r = 10%, $r_1$ = x%
loss % = ${r × (100 - r_1)}/100 - r_1$
–1 = ${100 × (100 - x)}/100 - x$
(–ve sign for loss)
–100 = 1000 - 10x - 100x
+110x = 1100
x = 10% ⇒ r1 =10%
Question : 4
A dealer marks his goods at 40% above the cost price and allows a discount of 20% on the marked price. The dealer has a
a) gain of 25%
b) gain of 12%
c) loss of 12%
d) loss of 20%
Answer »Answer: (b)
Let the CP of article be Rs.100.
Marked price = Rs.140
S.P. = ${140 × 80}/100$ = Rs.112
Gain per cent = 12%
Using Rule 8,
Here, r = 40%, $r_1$ = 20%
Required profit or loss %
= ${r × (100 - r_1)}/100 - r_1$
= ${40 × (100 - 20)}/100 - 20$
= ${40 × 80}/100 - 20$
= 32 - 20 = 12% profit
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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