find distance only section 6 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 10 km
(b) 40 km
(c) 20 km
(d) 25 km
The correct answers to the above question in:
Answer: (a)
Discuss Form
Read more type 2 section 6 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Deepak starts walking straight towards east. After walking 75 metres, he turns to the left and walks 25 metres straight. Again he turns to the left, walks a distance of 40 metres straight, again he turns to the left and walks a distance of 25 metres. How far is he from the starting point ?
a) 115 metres
b) 50 metres
c) 25 metres
d) 140 metres
e) None of these
Answer »Answer: (e)
The movements of Deepak are as shown in Figure.
Claerly, EB = DC = 40m.
∴ Deepak's distance from the starting point A
= (AB - EB) = (75 - 40)
= 35 m.
Question : 2
A man starts walking from a point and walks 12 kms towards north. He turns 90° left and walks a distance and stopped. If the distance between initial point and final positions is 13 kms , how much distance he travelled after turning from the North?
a) 5 kms
b) 2 kma
c) 1 km
d) 7 kms
Answer »Answer: (a)
BC = $√{13^2 + 12^2}$
= $√{169 + 144}$
= $√{25}$ = 5 km
Question : 3
Abhay travelled 9 km Northwards, turned left and travelled 5 km, then turned left again and travelled 9 km. How far is Abhay from the starting point?
a) 9 km.
b) 14 km
c) 5 km.
d) 4 km.
Answer »Answer: (c)
AD = 5 km.
DIRECTIONS:
- Point A is 8 m west of point B.
- Point E is 2 m east of point F.
- Point G is 3 m east of point H.
- Point E is 3 m north of point of point D.
- Point C is 9 m west of point D.
- Point G is 9 m north of point F.
- Point C is 6 m south of point B.
Question : 4
A person starts from point G in east direction. Walks for 6 m, takes a right turn, now walks for 5 m. Now he takes a left turn, walks for 3 m, then after two consecutive right turns he reaches point E. Find the distance travelled by him to reach point E.
a) 25 m
b) 23 m
c) 27 m
d) 24 m
e) 28 m
Answer »Answer: (a)
6 + 5+ 3 + (9-5) + (3+4) = 25 m
Question : 5
Find distance AH.
a) $7√5 m$
b) $6√6 m$
c) $7√6 m$
d) $6√5 m$
e) None of these
Answer »Answer: (d)
Vertical distance = GF – (CB – ED) = 9 – (6-3) = 6
Horizontal distance = AB + (CD – (HG + FE)) = 8 + (9 – (3+2) = 12
Required distance AH = $√ (6^2 + 12^2 ) = 6√5 m$
DIRECTIONS:
- Point B is 9 km east of point A.
- Point T is 6 km south of point B.
- Point S is 4 km west of point T.
- Point T is 8 km west of point G.
Question : 6
A person is standing on midpoint of line TG. Find his shortest distance from point B?
a) $5√14 km$
b) $6√3 km$
c) $3√15 km$
d) $2√13 km$
e) None of these
Answer »Answer: (d)
Let that point be Y. So Midpoint of TG means TY = $8/2$ = 4 km
So BY = $√(BT^2 + TY^2 ) = √ (6^2 + 4^2 ) = 2√13 km$
GET direction & distance sense test PRACTICE TEST EXERCISES
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